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Anit [1.1K]
3 years ago
15

Select "Rational" or "Irrational" to classify each number.

Mathematics
2 answers:
eduard3 years ago
6 0
1. Rational.
2. Irrational (famous for being irrational).
3. Rational.
4. I think this is irrational.
Sati [7]3 years ago
3 0

Rational: A number is rational if it can be written in the form of p/q, where q≠0, and it is terminating if q is of the form 2^{m} or 5^{n} or 2^{m} \times 5^{n} where m and n are whole numbers or non terminating repeating.

Irrational number: A number which can't be written in the form of p/q, i.e the number after decimal does not terminates.It is non terminating repeating.

1. 2/3 =0.66666...(non terminating repeating)   = Rational

2. π  =3.14159 26535 ........(non terminating non repeating)=Irrational

3.√400 =20 (terminates)=Rational

4. 36√2 = as √2=1.414.....(non terminating non repeating)=Rational×Irrational=Irrational

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liubo4ka [24]

The first two are 6 and 28. The factors of 6 add up to the same thing as 6.

Six

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1 + 2 + 3 = 6

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This one is kind of hard to believe

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The vertex of a parabola represented by f(x)=x^2 - 4x + 3 has coordinates (2,-1). Find the coordinates of the vertex of the para
Step2247 [10]
f(x)=x^2-4x+3
a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:
f(x)=a(x-p)^2+q
f(x)=1(x-2)^2-1

We need to put (x-2) at the place of (x) in f(x) equation to get g(x)
g(x)=1[(x-2)-2]^2-1
g(x)=(x-2-2)^2-1
g(x)=(x-4)^2-1
So:
p=4, q=-1

Vertex of the parabola defined by g(x)=f(x-2) has the vertex at \boxed{(4;-1)}

:)
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