The given function is,

The graph can be drawn as,
The period will be distance between two consequetive maximas,

Thus, period is correct.
The amplitude can be determined as,

Thus, amplitue is incorrect.
The range is,

Thus, the range is correct.
The midline is,

Thus, the midline is correct.
Thus, option (b) is the solution.
X - 4y = 2.....multiply by -3
3x + 2y = 6
-------------
-3x + 12y = -6 (result of multiplying by -3)
3x + 2y = 6
------------add
14y = 0
y = 0
3x + 2y = 6
3x + 2(0) = 6
3x = 6
x = 6/3
x = 2
solution is (2,0).....so the graph that has the two lines intersecting (crossing) at (2,0) is gonna be ur graph
Answer:
flaimgo/albert
Step-by-step explanation:
Answer:
The correct option is C). (9,4)
The coordinates of a point N is (9,4)
Step-by-step explanation:
Theory: If point P(x,y) lies on line segment AB and AP: PB=m:n, then we say P divides line AB internally in ratio of m:n and Point is given by
P=
Given that point, M is lying somewhere between point L and point N.
The coordinates of a point L is (-6,14)
The coordinates of a point M is (-3,12)
Also, LM: MN = 1:4
We can write as,
Let,
Point L(-6,14)=(X1, Y1)
Point M(-3,12)=(x,y)
Point N is (X2, Y2)
m=1 and n=4
M(-3,12)=
M(-3,12)=
M(-3,12)=

(-15)=X2-24
X2=9

(60)=Y2+56
Y2=4
Thus,
The coordinates of a point N is (9,4)
Result: The correct option is C). (9,4)