QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
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Step-by-step explanation:
if 5s=3h
34s=?
we will criss cross and
<u>5sx</u><u>?</u>=<u>3h</u><u>×</u><u>34s</u><u> </u>
<u>5s</u><u> </u> <u>5s</u>
=19.5h
