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3 years ago

Please help 100 points and I will give brainliest for helping me out

Mathematics

1 answer:

deff fn [24]3 years ago

6 0

Answer:

I think its telling you to done o and up and like 2y 1x

Step-by-step explanation:

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What is the area to this? (number 4)

IrinaK [193]

Use the formula 1/2(base1+base2)height. Substitute the values.

7 0

3 years ago

In △ABC, ∠C is a right angle and sinB=725.

scoundrel [369]

9514 1404 393

Answer:

A 7/25

Step-by-step explanation:

The cosine of an angle is equal to the sine of its complement. In a right triangle, angle A is the complement of angle B. So, ...

cos(A) = sin(B)

cos(A) = 7/25

8 0

2 years ago

56 students signed up for the school play. About 34% of these students were boys. At the auditions only 31 girls attended. What

Elza [17]

56 students represents 100 % and

X boys represent 34%,

so x= 56•34/100= 19.04 so approximately 19 boys

56-19= 37 girls signed up.

Now 37 girls represent 100% and 31 girls represent x % ,

So x= 31•100/37= 83.78% about 84% of the girls attended

3 0

3 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

3 years ago

Can some one help me answer these questions?

attashe74 [19]

Answer:

B. A value of x = 27 results in congruent triangle.

5 0

3 years ago