Answer:
The standard error of the proportion is 0.0485.
Step-by-step explanation:
The standard error of a proportion p in a sample of size n is given by the following formula:
![SE_{m} = \sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=SE_%7Bm%7D%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
In this problem, we have that:
![n = 100, p = 0.38](https://tex.z-dn.net/?f=n%20%3D%20100%2C%20p%20%3D%200.38)
![SE_{m} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.38*0.62}{100}} = 0.0485](https://tex.z-dn.net/?f=SE_%7Bm%7D%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B0.38%2A0.62%7D%7B100%7D%7D%20%3D%200.0485)
The standard error of the proportion is 0.0485.
Answer:
In the year 2010, the population of the city was 175,000
Step-by-step explanation:
If we rewrote this as a linear expression in standard form (it is linear, btw), it would look like this:
![P(t)=\frac{11}{2}t+175](https://tex.z-dn.net/?f=P%28t%29%3D%5Cfrac%7B11%7D%7B2%7Dt%2B175)
The rate of change, the slope of this line, is 11/2. If the year 2010 is our time zero (in other words, we start the clock at that year), then 0 time has gone by in the year 2010. In the year 2011, t = 1 (one year goes by from 2010 to 2011); in the year 2012, t = 2 (two years have gone by from 2010 to 2012), etc. If we plug in a 0 for t we get that y = 175,000. That is our y-intercept, which also serves to give us the starting amount of something time-related when NO time has gone by.
Answer:
54 minutes
Step-by-step explanation:
45 minutes per 2.5 miles
45/2.5 = 18 minutes per mile
3 miles* 18 minutes= 54 miles
Answer:
JRJGJGJGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG
Step-by-step explanation: