Answer:
The 99% confidence interval for the average fluid content of a can is between 11.54 and 12.66 fluid ounces.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of ). So we have T = 2.797
The margin of error is:
M = T*s = 2.797*0.2 = 0.56
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12.1 - 0.56 = 11.54 fluid ounces.
The upper end of the interval is the sample mean added to M. So it is 12.1 + 0.56 = 12.66 fluid ounces.
The 99% confidence interval for the average fluid content of a can is between 11.54 and 12.66 fluid ounces.
Divide the total by the quantity of numbers:
84 / 3 = 28
This is the middle number.
The other numbers would be 1 lower ( 28-1 = 27) and 1 higher (28 +1 = 29)
The largest number would be 29.
Answer:
A. 5x - 1
Step-by-step explanation:
3x - 2
+ 2x + 1
------------
5x-1
Answer:
60°
Step-by-step explanation:
All the sides are of equal length, 12,12,12 , 60,60, ?, so it is 60
Let's look at the picture, let's imagine that the gray line is the perimeter fence and that the red OR the blue is the one dividing it. We can see that the blue line is longer than the red one, so it will be advantageous, to have a bigger area, to have the dividing fence the smallest possible.
Let's say then that the width (W) is bigger (or equal) to the length (L), so we have:
The area is W*L, so we have
this function is a parabola facing down, its zeros are 0 and 80, therefore its maximum is when L=40
hence, L=40 and W=(240-120)/2=60
It will be a rectangle, measuring 60x40 and the divinding fence will be 40