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2 years ago

Review from 2.3 and 2.4: Equation: y = (-2/3)x + 1/8 What is the slope?

Mathematics

1 answer:

son4ous [18]2 years ago

4 0

Answer:

The slope is m = -2/3

Step-by-step explanation:

Use the slope intercept form y = mx + b to find the slope m

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Points (0, 0) and (x, y) ?

kap26 [50]

Answer:

m=y/x

Step-by-step explanation:

8 0

2 years ago

Adult tickets for the school musical sold for $3.50 and students tickets sold for $2.50. 321 tickets were sold altogether for $9

Licemer1 [7]

186 student tickests were sold and 135 adult tickets were sold

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2 years ago

Correct Number Formats

IrinaK [193]

Answer:

Step-by-step explanation: From the above question, we have been given some hints to assist in the number interpretation.

Answers are:

-4.99

1.9435

3.25E4

1.56e-9

The above selected numbers have been selected using the hints below:

You cannot have commas in numbers.

You cannot have a space in a number.

You cannot substitute the letter O for zero or the letter l for 1.

You cannot include the units or a dollar sign in the number.

You can have the sign of the number, + or -.

3 0

3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

8 1/3 subtract 2 2/3

deff fn [24]

Answer:

5 2/3........................

4 0

2 years ago