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2 years ago

Simplify 2^3 • 2^7 answer quick pls lol

Mathematics

2 answers:

aliina [53]2 years ago

7 0

Answer:

2¹⁰

Step-by-step explanation:

pretty sure you add exponents to simplify them

yarga [219]2 years ago

3 0

Answer:

It's A.

Step-by-step explanation:

2^3 •2^7 = 1024

2^10 = 1024

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How do you solve 10+5(3x-4)=2x+7

Taya2010 [7]

Answer:

$x=1\dfrac{4}{13}$

Step-by-step explanation:

Given the equation

$10+5(3x-4)=2x+7$

Use distributive property:

$10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7$

Use commutative property to rewrite the equation:

$15x+10-20=2x+7$

$15x-10=2x+7$

Add 10 th both sides:

$15x-10+10=2x+7+10\\ \\15x=2x+17$

Subtract $2x:$

$15x-2x=2x+17-2x\\ \\13x=17$

Divide by 13:

$x=\dfrac{17}{13}=1\dfrac{4}{13}$

4 0

3 years ago

Write three (3) scenarios that describe three different real-world functions. Each scenario should use two of the variables from

NISA [10]

Here is one Jake’s salary depends on the number of hours he works.
The independent variable is the number of hours and the dependent variable is salary.
Let x = the number of hours worked
Let y = Jake's salary
The set of ordered pairs {(1, 10), (2, 20), (3, 30), (4, 40), (5, 50)} can be used to represent
the function, assuming Jake earns $10 per hour.

8 0

2 years ago

Graph the line that goes through the point (-6,-2) with slope of 1

vekshin1

Answer:

<h2>Check out the image.</h2>

Step-by-step explanation:

Let, the equation of the straight line is y = mx + c; where m is the slope of the equation and c is the constant.

The line has the slope 1.

Hence, the equation becomes y = x + c.

Since, the line passes through (-6, -2), -2 = -6 + c or, c = 4.

Hence, the equation of the straight line becomes y = x + 4.

Putting x = 0, we get, y = 4.

The line passes through (0, 4).

7 0

2 years ago

a supermarket sells 2 kg and 4 kg of sugar a shipment of 1100 bags of sugar has a total mass of 2900 kg. How many 2 kg bags and

Vaselesa [24]

There are 750 (2 kg) bags and 350 (4 kg) bags in the shipment

Step-by-step explanation:

The given is:

A supermarket sells 2 kg and 4 kg of sugar a shipment of 1100 bags of sugar
The total mass of the sugar is 2900 kg

We need to find how many 2 kg bags and 4 kg bags are in the shipment

Assume that x represents the number of 2 kg bags and y represents the number of 4 kg bags

∵ x is the number of 2 kg bags

∵ y is the number of 4 kg bags

∵ The total number of bags are 1100

- Add x and y, then equate the sum by 1100

∴ x + y = 1100 ⇒ (1)

∵ The total mass of sugar is 2900 kg

- Multiply x by 2 and y by 4 to find the mass of the bags, then

add the two product and equate them by 2900

∴ 2x + 4y = 2900 ⇒ (2)

Now we have a system of equations to solve it

Multiply equation (1) by -2 to eliminate x

∴ -2x - 2y = -2200 ⇒ (3)

- Add equations (2) and (3)

∴ 2y = 700

- Divide both sides by 2

∴ y = 350

- Substitute the value of y in equation (1) to find x

∵ x + 350 = 1100

- Subtract 350 from both sides

∴ x = 750

There are 750 (2 kg) bags and 350 (4 kg) bags in the shipment

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

#LearnwithBrainly

4 0

2 years ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

case A) point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

case B) point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

case C) point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

case D) point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

case E) point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

case F) point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

the answer is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

2 years ago

Read 2 more answers