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ikadub [295]
3 years ago
14

Is 0/2 a repeating or terminating?

Mathematics
1 answer:
daser333 [38]3 years ago
3 0

<em>Terminating.</em>

<em></em>

<em></em>

<em></em>

<em></em>

<h2><em>Please Mark Brainliest Ty!<3</em></h2>

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artcher [175]

Answer:

EBD is 135, ABE is 45

Step-by-step explanation:

5 0
3 years ago
2+X/9 = 5x-6/27 SOLVE.
oksano4ka [1.4K]

Answer:

x = 6

Step-by-step explanation:

First, we need to cross multiply on both sides, which gives us:

9 * (5x - 6) = 27 * (2 + x)

45x - 54 = 54 + 27x

Now, we want to isolate x on either side.

We can substract 54 from both sides:

(45x - 54 = 54 + 27x) - 54

45x - 108 = 27x

We then subtract 45 from both sides:

(45x - 108 = 27x) - 45

-108 = -18x

Finally, we divide both sides by -18:

(-108 = -18x) / -18

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6 0
2 years ago
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Answer:

im not very good at geometry but is there any choices you could pick from

Step-by-step explanation:


4 0
3 years ago
A bank loaned out $28,500, part of it at the rate of 14% annual interest, and the rest at 4% annual
Flauer [41]

Answer:

$15,000 was invested at 14% per year, and $13,500 was invested at 4% per year.

Step-by-step explanation:

Given that a bank loaned out $ 28,500, part of it at the rate of 14% annual interest, and the rest at 4% annual interest, and the total interest earned for both loans was $ 2,640.00, to determine how much was loaned at each rate you must perform the following calculations:

28,500 x 0.14 + 0 x 0.04 = 3,990

20,000 x 0.14 + 8,500 x 0.04 = 3,140

15,000 x 0.14 + 13,500 x 0.04 = 2,640

Therefore, $ 15,000 was invested at 14% per year, and $ 13,500 was invested at 4% per year.

5 0
3 years ago
Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. Y=4.5 when x = 3
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\bf \qquad \qquad \textit{inverse proportional variation}\\\\&#10;\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;y=4.5\\&#10;x=3&#10;\end{cases}\implies 4.5=\cfrac{k}{3}\implies 4.5(3)=k&#10;\\\\\\&#10;13.5=k\qquad therefore\qquad \boxed{y=\cfrac{13.5}{x}}
8 0
3 years ago
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