In a standard equation of dividing a two digit divisor one must follow these steps:
1. Double check if the first two digits of the dividend are equal or larger that the divisor. Start dividing if so.
2. Write the answer above the second digit (or third if the first two digits' value is smaller than the divisor).
3. Multiply the answer with the divisor and subtract it from the dividend (digits used).
4. From the answer to the subtraction, add the next digit to the right of the dividend and repeat process until you get the total quotient.
5. In cases of remainders (extra numbers not divisible by the divisor), write them to the right of the quotient.
Please see attached picture for reference.
Hope this helps.
Answer:
The answer is 0.426
Step-by-step explanation:
10 to the power of 2 is 100 because 10 x 10= 100 when you divide a decimal by 100 just move the decimal point 2 times to the left
Answer: 25
Step-by-step explanation:
We know that
cos a+cos b=cos[(a+b)/2]*cos[(a-b)/2]
we have
<span>cos(π/7)+cos(2π/7)+cos(3π/7)+cos(4π/7)-------------> equation 1
</span>cos(4π/7)+cos(2π/7)=cos[(4π/7+2π/7)/2]*cos[(4π/7-2π/7)/2]
=cos(3π/7)*cos(π/7)
then
cos(4π/7)+cos(2π/7)=cos(3π/7)*cos(π/7)--------------> equation 2
[cos(3π/7)+cos(π/7)]=cos[(3π/7+π/7)/2]*cos[(3π/7-π/7)/2]
=cos(2π/7)*cos(π/7)
then
[cos(3π/7)+cos(π/7)]=cos(2π/7)*cos(π/7)-----------> equation 3
I substitute 2 and 3 in 1
[cos(3π/7)+cos(π/7)]+[cos(4π/7)+cos(2π/7)]
{cos(2π/7)*cos(π/7}+{cos(3π/7)*cos(π/7)}
=cos(π/7)*[cos(2π/7)+cos(3π/7)]
the answer is
cos(π/7)+cos(2π/7)+cos(3π/7)+cos(4π/7)=cos(π/7)*[cos(2π/7)+cos(3π/7)]
Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
![\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccl%7Dt%26h%28t%29%26Description%5C%5C0%2620%26Initial%20%5C%20height%5C%5C0.5%2618.8%26Rock%20%5C%20in%20%5C%20downward%20%5C%20motion%5C%5C1%2615.1%26%5C%5C1.5%269%26%5C%5C2%260.4%26The%20%5C%20height%20%5C%20just%20%5C%20before%20%5C%20the%20%5C%20rock%20%5C%20hits%20%5C%20the%20%5C%20ground%20%5C%5C2.5%26-10.6%26The%20%5C%20calculated%20%5C%20height%20%5C%20after%5C%20the%20%5C%20rock%20%5C%20hits%20%5C%20the%20%5C%20ground%20%5C%5C3%26-24.1%26Calculated%20%5C%20height%20%5C%20after%5C%20the%20%5C%20rock%20%5C%20hits%20%5C%20the%20%5C%20ground%5Cend%7Barray%7D)
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.