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3 years ago

The factory buys the new machine to replace the other two, which of the following expressions show the increase in sate?

Mathematics

1 answer:

Leokris [45]3 years ago

8 0

Answer:

can you change this picture?

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A 0.143-Henry Inductor is connected in series with a variable resistor to a 208-volt 400-cycle source. For what value of capacit

aleksandr82 [10.1K]

Answer:

A.)359.2, B.)2.5 uf

Step-by-step explanation:

E / I = R

208 / 1.04 = 200 ohms

2*pi*f*L = Xl

6.28*400*.143 = 359.2 ohm

1 / (2*pi*f*Xc) = c

1 /(6.28*400*159.2) = 2.5 uf

8 0

3 years ago

Rewrite the following equation in slope-intercept form. x + 5y = -11 Write your answer using integers, proper fractions, and imp

AveGali [126]

Answer:

$\displaystyle y = -\frac{x}{5} - 2\frac{1}{5}$

Step-by-step explanation:

$\displaystyle x + 5y = -11 → 5y = -x - 11 → \frac{5y}{5} = \frac{-x - 11}{5} \\ \\ y = -\frac{1}{5}x - 2\frac{1}{5}$

I am joyous to assist you at any time.

7 0

3 years ago

Decimal Operati 1. Find the sum of the expression. 0.975 + 3.8

BlackZzzverrR [31]

Answer:

4.775

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated, filming up full rows of

AleksandrR [38]

6 rows are empty.

112/7 = 16 rows

70/7 = 10 rows used.

4 0

3 years ago

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

Given:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

Value of x:

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

6 0

3 years ago