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Varvara68 [4.7K]
2 years ago
15

Write the equation for a line that is perpendicular to the line y = −1 and passing

Mathematics
1 answer:
zheka24 [161]2 years ago
8 0

Answer:

x= 12

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the gradient and c is the y-intercept.

y= -1

y= 0x -1

The given line, y= -1, is a horizontal line as it has a gradient of zero.

A line perpendicular to a horizontal line is a vertical line, and its equation is written as x= ___.

Since the vertical line passes through the point (12, -39), its equation is x= 12.

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<h3>What are trigonometric functions?</h3>

Trigonometric functions are used to establish the relationship between the sides and the angles of a right angle triangle.

Analysis:

If cos∅ = adjacent/hypotenuse =  12/13,

Then, opposite of the right angled triangle = \sqrt{13^{2} - 12^{2}  } = 5

sin∅ = 5/13, cos∅ = 12/13, tan∅ = 5/12

sin(2∅) = 2sin∅cos∅ = 2(5/13)(12/13) = 120/169

cos(2∅) = cos^{2}∅ - sin^{2}∅ = (\frac{12}{13}) ^{2} - (\frac{5}{13} )^{2} = 144/169 - 25/169 = 119/169

tan(2∅) = sin(2∅) / cos(2∅)  = 120/169 ÷ 119/169 = 120/119

Learn more about trigonometric functions: brainly.com/question/24349828

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