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meriva
3 years ago
8

Hello everyone, how are you? But well, can you follow me? please​

SAT
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

Sure, I will.

Explanation: I just will because you asked.

Alenkasestr [34]3 years ago
7 0

Answer:

<h3>Hi!!!</h3>

Explanation:

<h2>Yes I did....thx for following me back...</h2>

Brainliest pls!

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During the halftime performance for a football game, the color guard is planning a new formation in which seven members stand ar
shtirl [24]

There are different kinds of angles. The measure of each exterior angle of the formation is 51.4.

<h3>What is a exterior angle in math?</h3>

The term exterior angle is known to be the angle that is found between a side of a polygon and that of an extended adjacent side.

The shape of the halftime is regular heptagon.

Note that a  regular heptagon has 7 congruent sides and 7 congruent interior angles.

So the exterior angles are said to be congruent, based on the fact that angles supplementary to congruent angles are  regarded as congruent.

So Let take n as the measure of each exterior angle.

7n = 360

n= 360/n

To Solve for n =51.4

Therefore, The measure of each exterior angle of the formation is 51.4.

Learn more about exterior angle from

brainly.com/question/2546141

5 0
2 years ago
Calculate the amount of heat necessary to raise the temperature of 135. 0 g of water from 50. 4°f to 85. 0°f. The specific heat
Snowcat [4.5K]
안녕 나는 새로운 무엇을 할까 안녕 안녕 나는 여자야 내 사촌 소년은 친구였어!!
3 0
2 years ago
You have a home with a market value of $144,700, which has an assessment value of 72% of that amount. your city has a property t
poizon [28]

If you have a home with a market value of $144,700,The amount of taxes that went to funding schools is:c.$2,641.

<h3>
Tax amount
</h3>

First step

Assessment value= $144,700 × 0.72

Assessment value= $104,184

Second step

Tax on property=$104,184 × 0.039

Tax on property = $4,063.176

Third step

Funding school taxes=$4,063.176 × 0.65

Funding school taxes= $2,641

Therefore the amount of taxes that went to funding schools is:c.$2,641.

Learn more about taxes here:brainly.com/question/13941741

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4 0
3 years ago
A species of mud snail was studied for five years. During this time, scientists observed the season in which they mated, the num
Doss [256]

Answer:

The answer is B.

Explanation:

"stressors as drought, famine, and lack of mates."

4 0
3 years ago
Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM
Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

<em>#include <cmath></em>

<em>#include "pppm_tip4p.h"</em>

<em>#include "atom.h"</em>

<em>#include "domain.h"</em>

<em>#include "force.h"</em>

<em>#include "memory.h"</em>

<em>#include "error.h"</em>

<em>#include "math_const.h"</em>

<em />

<em>using namespace LAMMPS_NS;</em>

<em>using namespace MathConst;</em>

<em />

<em>#define OFFSET 16384</em>

<em />

<em>#ifdef FFT_SINGLE</em>

<em>#define ZEROF 0.0f</em>

<em>#define ONEF  1.0f</em>

<em>#else</em>

<em>#define ZEROF 0.0</em>

<em>#define ONEF  1.0</em>

<em>#endif</em>

<em />

<em>void PPPMTIP4P::init()</em>

<em>{</em>

<em>  // TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms</em>

<em />

<em>  if (force->newton == 0)</em>

<em>    error->all(FLERR,"Kspace style pppm/tip4p requires newton on");</em>

<em />

<em>  PPPM::init();</em>

<em>}</em>

<em />

<em>void PPPMTIP4P::particle_map()</em>

<em>{</em>

<em>  int nx,ny,nz,iH1,iH2;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))</em>

<em>    error->one(FLERR,"Non-numeric box dimensions - simulation unstable");</em>

<em />

<em>  int flag = 0;</em>

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;</em>

<em>    ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;</em>

<em>    nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;</em>

<em />

<em>    part2grid[i][0] = nx;</em>

<em>    part2grid[i][1] = ny;</em>

<em>    part2grid[i][2] = nz;</em>

<em />

<em>    if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||</em>

<em>        ny+nlower < nylo_out || ny+nupper > nyhi_out ||</em>

<em>        nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;</em>

<em>  }</em>

<em />

<em>  int flag_all;</em>

<em>  MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);</em>

<em>  if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");</em>

<em>}</em>

<em>void PPPMTIP4P::make_rho()</em>

<em>{</em>

<em>  int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;</em>

<em>  FFT_SCALAR dx,dy,dz,x0,y0,z0;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];</em>

<em>  for (i = 0; i < ngrid; i++) vec[i] = ZEROF;</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double *q = atom->q;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = part2grid[i][0];</em>

<em>    ny = part2grid[i][1];</em>

<em>    nz = part2grid[i][2];</em>

<em>    dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;</em>

<em>    dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;</em>

<em>    dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;</em>

<em />

<em>    compute_rho1d(dx,dy,dz);</em>

<em />

<em>    z0 = delvolinv * q[i];</em>

<em>    for (n = nlower; n <= nupper; n++) {</em>

<em>      mz = n+nz;</em>

<em>      y0 = z0*rho1d[2][n];</em>

<em>      for (m = nlower; m <= nupper; m++) {</em>

<em>        my = m+ny;</em>

<em>        x0 = y0*rho1d[1][m];</em>

<em>        for (l = nlower; l <= nupper; l++) {</em>

<em>          mx = l+nx;</em>

<em>          density_brick[mz][my][mx] += x0*rho1d[0][l];</em>

<em>        }</em>

<em>      }</em>

<em>    }</em>

<em>  }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

6 0
2 years ago
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