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3 years ago

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Funke, Adamu, Shehu, Kwame and Tanko play a game of cards. Funke says to Adamu, "If you give me 5 cards, you will have as many a

s Tanko has and if I give you 4 cards, you will have as many as Kwame has."Funke and Adamu together have 13 cards more than what Kwame and Tanko together have. If Adamu has 2 cards more than what Shehu has and the total number of cards be 133, how many cards does Adamu have?

1 answer:

baherus [9]3 years ago

5 0

This involves basic arithmetic calculations and simultaneous equations.

Adamu has 25 Cards

Let the following letters represent the number of cards each has;

A: ADAMU

F: FUNKE

S: SHEHU

K: KWAME

T: TANKO

If adamu gives funke 5 cards, he will have as many as tanko. Thus;

A - 5 = T --- eq 1

If funke gives adamu 4 cards, he will have as many as kwame. Thus;

A + 4 = K --- eq 2

Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;

A + F = K + T + 13 --- eq 3

Adamu has 2 cards more than what Shehu has. Thus;

A - 2 = S --- eq 4

From online research, the Total Number of cards is 134 and not 133. Thus;

A + F + K + S + T = 134 --- eq 5

Let's put A - 5 = T and A + 4 = K in eq 3 to get;

A + F = (A + 4) + (A - 5) + 13

A + F = 2A + 12

F = 2A - A + 12

F = A + 12

Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;

A + A + 12 + A + 4 + A - 2 + A - 5 = 134

Simplifying gives;

5A + 9 = 134

5A = 134 - 9

5A = 125

A = 125/5

A = 25

Adamu has 25 Cards

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Problems of normally distributed samples are solved using the z-score formula.

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This is 1 subtracted by the pvalue of Z when X = 4.2. So

$Z = \frac{X - \mu}{\sigma}$

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They last at least 4.3 minutes

7 0

3 years ago