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STALIN [3.7K]
3 years ago
14

un avión supersónico puede volar con una rapidez de 1225 km. qué distancia recorrería son esa rapidez en 12.5 h

Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

98km

Step-by-step explanation:

SPANISH:

 La distancia recorrida por el avion supersonico es de : d = 98km

   V = 1225km/h

   d = ?

   t = 12.5h

Para la solucuión se aplica la ecuación del movimiento rectilineso uniforme como se muestra a continuación :

  V = d / t

  d = V / t

  d = 1225km/h / 12.5H

 d = 98km

ENGLISH:

The distance traveled by the supersonic plane is: d = 98km

    V = 1225km / h

    d =?

    t = 12.5h

For the solution, the equation of the uniform rectilinear motion is applied as shown below:

   V = d / t

   d = V / t

   d = 1225km / h / 12.5H

  d = 98km

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1)  =  H

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