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STatiana [176]
3 years ago
7

Instantaneous rate of change

Mathematics
2 answers:
ch4aika [34]3 years ago
4 0

Answer:

h(x) =  \frac{d}{dx} (3 {x}^{2}  - 4) \\  = 6x. \\ now \\ x =  - 3 \\ h(x) \\ h( - 3) \\  = 6( - 3) =  - 18.

Alex777 [14]3 years ago
3 0

Find derivative of h(x)

\\ \sf\longmapsto \dfrac{d}{dx}(3x^2-4)

\\ \sf\longmapsto 6x

Now

x=-3

\\ \sf\longmapsto h(-3)

\\ \sf\longmapsto 6(-3)=-18

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Rewrite 85% as a fraction in simplest form and as a decimal
nignag [31]

85 %

85/100 - divide by 5 for the numerator and denominator

85/5= 17

100/5=20

Simplest form : 17/20

As decimal : 0.85 because of 85/100

Answer:

Simplest form : 17/20

As decimal : 0.85

3 0
3 years ago
Rewrite the following equation in slope-intercept form. 4x - y =12
Vlad [161]
Y=4x-12 hope this helps :)
3 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
What does point g represent
Gnom [1K]
Do you have a picture?
7 0
3 years ago
Please help me! Sorry if the image is blurry.
liq [111]

Answer:

B) 27

Step-by-step explanation:

(-3,27)

(-1,19)

(0,15)

(2,7)

4 0
3 years ago
Read 2 more answers
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