The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
brainly.com/question/24369824
#SPJ1
The answer is for a fact c
Answer:
John have $36 and he should give $48 to his brother for both to have equal money.
Step-by-step explanation:
Given that,
amount of money John have = $84
amount of money John's brother owed to her friend = $12
$12 of the $84 is going to his brother's friend, that leaves $72 for John and his brother.
If they are to finish with the same amount, then each should have half of the John's money after he paid $12
So,
72/2
= 36 each
but since John's brother have to give 12 rupees in debt so
36+12
= $48
So John should have $36 and he should give $48 to his brother.
Answer:
25 Or A
Step-by-step explanation:
