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ollegr [7]
2 years ago
7

Find an equation for the linear function g(x) which is perpendicular to the line 5x-2y=6 and intersects the line 5x-2y=6 at x=12

.
Mathematics
1 answer:
exis [7]2 years ago
8 0

Answer:

≡

Step-by-step explanation:

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What number is 24% of 80
jonny [76]
Hi

24% of 80 is 19.2

100% ⇒ 80
24% ⇒ x 

100x = 24·(80)
100x = 1920
x = 1920/100
x = 19.2


3 0
2 years ago
Sove for q.<br> s = 4p + 4q
sergey [27]
S=4P+4Q S=4(P+Q) S/4=P+Q S/4-P=Q Q=S/4-P
4 0
3 years ago
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What is the length of feet in 5 equal length of ribbon equaling 2 yards of ribbon
alisha [4.7K]
Am presuming you are asking for the length of each ribbon in feet.

5 of them = 2 yards.

1 of them =  2/5 = 0.4 yards.

But note 3 feet make 1 yard.

Therefore:  0.4 yards = 0.4 * 3 feet =  1.2 feet.
3 0
2 years ago
The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20
drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, P=P_0e^{bt}

where, P_0 and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

9600=P_0e^{b\times 0}

So, P_0=9600

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\

\ln(23/12}=6b \\\\

b = \frac{\ln{1.92}}{6} \\\\

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

P=9600 \times e^{0.109\times t}

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

P=9600 \times e^{0.109\times 15}=49243

Hence, the population of the rabbit in 2009 is 49243.

7 0
3 years ago
Can you halp me please with the number 8
emmasim [6.3K]
Look at each pie differently, there is 3 cherry between the four families so that is 3/4 cherry

and 2 apple so 2/4 which can be simplified to 1/2 

so your answer is b
8 0
3 years ago
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