What is the greatest common factor (GCF) of 28 and 36

Is the mean age at which American children learn to walk less than 15 months? A study of 40 American children found a mean walki

Sonbull [250]

Answer:

We define the random variable X as the walking age and we are interested if American children learn to walk less than 15 months so then that would be the alternative hypothesis and the complement would be the null hypothesis.

Null hypothesis: $\mu \geq 15$

Alternative hypothesis: $\mu$

And for this case the best answer would be:

H 0 : μ ≥ 15 vs. Ha : μ < 15

Step-by-step explanation:

We define the random variable X as the walking age and we are interested if American children learn to walk less than 15 months so then that would be the alternative hypothesis and the complement would be the null hypothesis.

Null hypothesis: $\mu \geq 15$

Alternative hypothesis: $\mu$

And for this case the best answer would be:

H 0 : μ ≥ 15 vs. Ha : μ < 15

And the data given from the sample is:

$\bar X = 13.2$ represent the sample mean

$\sigma$ represent the population deviation

$n = 40$ represent the sample size

And the statistic would be given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

8 0

3 years ago

A small, upscale boutique examines the income of 10 random households to determine if the community will be a good location for

USPshnik [31]

The correct answer for the question that is being presented above is this one: "D) The boutique will not locate a store in a community where everyone does not make at least $100,000. " The likely reason that the boutique chooses not to locate in the community is that the boutique will not locate a store in a community where everyone does not make at least $100,000.

7 0

3 years ago

Fill in the blank.<br> 19/2 =

Angelina_Jolie [31]

Answer:

9.5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A gym charges a $40 registration fee and $25 per month of membership. Create an equation to model the price (y) based on (x) mon

Lubov Fominskaja [6]

Answer:

y= 40 + 25x

Hope this helps!

8 0

3 years ago

How many ways are there for six dogs and four cats to sit in a row in a strawberry field so that no two cats sit next to each ot

pickupchik [31]

Answer: 5,760

Step-by-step explanation:

$\\$ It was given that each dog is distinct from other dogs and each cat is distinct from other cats, Also from the hint given, the First position is for the dogs. $\\$ Let D represent the dogs and C represent the Cat , then we have

$\\$ D C D C D C D C D D or

$\\$ D D C D C D C D C D or

$\\$ D C DD C D C D C D or

$\\$ D C D C D D C D C D or

$\\$ D C D C D C DD C D

$\\$ Each of the arrangements above could be done in

$\\$ 2 x 4! x 4! ( it is constant that D is starting , so I am only left with the arrangement of the remaining 5 D's , out of the remaining 5 D's it is also constant that tow of them will be together and this could be done in 2 ways, so I have 4! left for the D's and 4! also for the C's )

$\\$ = 2 x 24 x 24

$\\$ = 1 , 152

$\\$ The total arrangement = 5 x 1 , 152

$\\$ = 5,7 60 ways

3 0

3 years ago