9) Separate the polygon into 2 shapes (a rectangle and triangle). Then plug in the formula for those 2 shapes separately and add the 2 areas.
First, the triangle's area = bh x 1/2 or bh/2.
b=5 and h=5, so 5x5/2 or 25/2 = 12.5.
Next, solve the area for the rectangle(lw=A). l=5 and 2=8, so 5x8=40.
Add 40 +12.5 = 52.5cm^2 (always include units).
10) It is similar to the last problem. You will separate the polygon into 2 shapes (a circle and a square), but this time you will subtract the area of the sector formed from the circle (draw a dotted line where the circle would be formed in the square).
So, the area of the square is 2x2=4ft^2.
area of a circle is (pi)r2 or (pi)2^2= 4pi or about 12.5ft^2.
4+12.5 = 16.5 ft^2.
Now, the area of the sector must be subtracted from the combination of the 2 areas found above.
The area of a sector is 2(pi)r x (C/360).
The angle is given as 90°, the radius is 2 ft. Now plug these into the equation.
2(pi)(2)x(90/360) = 3.14ft^2.
16.5-3.14= 13.4 ft^2.
I have no Idea what you are saying sorry
Answer: I think the answer is 88.5%
Step-by-step explanation:
Step-by-step explanation:
a whole circle is 360°.
if you take away 40°, how many are left ?
that is absolutely the same as the question, when I have 15 apples and 6 are eaten, how many are left ?
well, 15-6 = 9 apples are left.
and so, 360-40 = 320° are left.
Answer:
Volume is 
Solution:
As per the question:
Diameter, d = 40 m
Radius, r = 20 m
Now,
From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:
iff
h(y) = cy + d
Then
when y = 1 m
h(- 20) = 1 m
1 = c.(- 20) + d = - 20c + d (1)
when y = 9 m
h(20) = 9 m
9 = c.20 + d = 20c + d (2)
Adding eqn (1) and (2)
d = 5 m
Using d = 5 in eqn (2), we get:
Therefore,
Now, the Volume of the pool is given by:
where
A = 
Thus
![V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}](https://tex.z-dn.net/?f=V%20%3D%20%5B-%20533.33cos%5Ctheta%20%2B%201000%5Ctheta%5D_%7B0%7D%5E%7B2%5Cpi%7D)
