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Georgia [21]
3 years ago
9

Below is the frequency distribution of the weights (in kg) of some sample of teen-agers.

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0
Omg i can not even read the hol thing it is too much
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John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs
mezya [45]

Answer:

The number of Pumpkin can used   = 48 cans

The number of Green Beans can used =   16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans =  3 :  1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of  John  wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used  = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m =  64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used  = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m =  16 cans

3 0
3 years ago
The perimeter of a rectangle is 84 Centimeters. the length is twice the width. find the length and width
KatRina [158]
Length= 28
Width= 14

Work:

2(2x)+2(x)=84
4x+2x=84
6x=84
x=14

14x2=28 (length)
6 0
3 years ago
Ken predicts that the average temperature will be −5°C in December. If he predicts the temperature will rise 6°C in January and
ipn [44]

Answer:

The equations [(-5) + (-3)] + 6 = -2 and [6 + (-5)] + (-3) = -2  he can use to find the sum of the temperatures for those months ⇒ 3rd , 5th

Step-by-step explanation:

i took the assignment

7 0
3 years ago
helppp asap :)) alyssa wants to play the game. choose the statement below that is correct in all aspects!
mars1129 [50]

help me plssssssssssss

6 0
3 years ago
Read 2 more answers
You have a bag full of apples. There are 12 Jonathan (red), 6 Granny Smith (green), and 3 Golden Delicious (yellow) apples in th
tensa zangetsu [6.8K]

Answer:

The total number of apples is 17

Step-by-step explanation:

(a)

Number of green apples = 4

P ( that all three apples are green)

= (limit 4 and 3) / (limit 17 and 3)

= 4! / 3!(4−3)!

= 17! / 3!(17−3)!

= 1 / 170

= 0.005

(b)

Number of red apples = 8

P(that all three apple are green)

=(limit 8 and 3) / (limit 17 and 3)

= 8! / 3!(8−3)!

= 17! / 3!(17−3)!

= 7 / 85

= 0.082

Now,

P(that no three apple is red)= 1−0.082 = 0.918

c)

P(of selecting 4 apple that contain at least 2 red apples)

= (limit 8 and 2) /( limit 17 and 2) X (2/15) + (limit 8 and 3) /(limit 17 / 3) X (1/14)

= (7/34) × (2/15) + (7/85) × (1/14)

= 0.027 + 0.058

= 0.085

d)

P(that the second apple selected is yellow given that the first apple is red)

= (limit 5 and 1) / ( limit 16 and 1)

= 5! / 1!(5−1)!

= 16! / 1!(16−1)!

= 5 /16

= 0.3125

5 0
3 years ago
Read 2 more answers
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