2 years ago

Below is the frequency distribution of the weights (in kg) of some sample of teen-agers.

Mathematics

1 answer:

Elan Coil [88]2 years ago

5 0

Omg i can not even read the hol thing it is too much

You might be interested in

Need some help with congruence and similarity <br> (Picture bellow)

DENIUS [597]

Answer:

a and b are similarity i think that's what your looking 4 idk

Step-by-step explanation:

8 0

3 years ago

Which expression simplifies 6(2 + x + x + y) using only 3 terms

almond37 [142]

Answer: 6(2+2x+1y)

Step-by-step explanation:

i think that is the anwser

4 0

3 years ago

What 3.405 ounces in expanded form

Y_Kistochka [10]

What you’re doing is breaking it down into its parts and writing it into an equation that way long hand.

3 + .4 + .00 + .005

7 0

3 years ago

There are 180 cars in the parking lot 30% are red cars how many red cards are there

Yuri [45]

There are 54 red cars

7 0

2 years ago

Read 2 more answers

AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of

defon

Answer:

Part 1) $m\angle AFE=55^o$

Part 2) $m\angle EFB=125^o$

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

<u>Note:</u> In this problem the correct measure of arc EA is 40 degrees (see the picture)

$m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)$

substitute the given values

$m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o$

Part 2) what is the measure of angle EFB?

we know that

$m\angle AFE+m\angle EFB=180^o$ ---> by supplementary angles (form a linear pair)

substitute the given value

$55^o+m\angle EFB=180^o$

$m\angle EFB=180^o-55^o=125^o$

8 0

3 years ago