the length of a rectangular room is 16 less than four times the width. the perimeter of the room is 68 feet. find the length and
the width
1 answer:
Answer:
Length = 30.4 ft
Width = 3.6 ft
Step-by-step explanation:
Width: x
Length: 4x + 16
2(x) + 2 (4x + 16) = 68
2x + 8x + 32= 68
10x = 68 - 32
x = 36/10
x = 3.6
Width = 3.6 ft
Length: 30.4 ft
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Answer:
Step-by-step explanation:
4x + 5x = 180 [They are angles on a "straight" line so they will add up to 180 degrees)
Answer: 125 ft cubed
Step-by-step explanation:
Answer: 91.8
cm
3
Explanation:
Volume of the box is
12.1
×
3.5 × 3.5= 148.225
cm
3
Each ball is
4
3
×
π
×
1.65
3
=
18.8165692
c
m
3
There are three balls
⇒
56.4497076
c
m
3
Subtract
⇒
148.225
−
56.4497076
=
91.7752924
c
m
3
V
empty space
=
91.775
c
m
3
Explanation:
V
box
=
l
⋅
w
⋅
h
=
12.1
⋅
3.5
⋅
3.5
=
148.225
c
m
3
V
each ball
=
4
3
π
r
3
=
4
3
π
(
3.3
2
)
3
=
4
3
π
(
35.937
8
)
c
m
3
V
3 balls
=
(
35.937
2
)
π
≈
56.450
c
m
3
V
empty space
=
148.225
−
56.450
=
91.775
c
m
3
Answer:
(-1,-4)
Step-by-step explanation:
(2, -1)
Moving down 3 means subtract 3 from the y value
Left 3 means subtract 3 from the x value
(2-3, -1-3)
(-1,-4)
