Three and two eight one thousandths
Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
Answer:5x times -7
Step-by-step explanation:
You ignore the brackets and move the 2x to the other side. Then move the 4 to the other side
Answer:
x=3
Step-by-step explanation:
lets take x as the number
so
6(x-3)=x-3
since it says "6 times" we know that we will have to multiply the difference by 6 and it says the difference of a number and 3 is equal to 3 less than the number so we know that we are subtracting 3 from x
6x-18=x-3
6x-x=18-3
5x=15
x=3
Answer:
7
Step-by-step explanation:
Simply subtract 6 from 13.
13-6=7
Hope this helps! :)
