Given:
Week 6 = 14 miles
Week 5 = 1.5 miles less than week 6.
1.5 miles is the common difference.
Week 6 = 14 miles
Week 5 = 12.5 miles
Week 4 = 11 miles
Week 3 = 9.5 miles
Week 2 = 8 miles
Week 1 = 6.5 miles
f(t) = first term + common difference(t-1)
f(t) = 6.5 miles + 1.5 miles (t-1)
f(1) = 6.5 + 1.5(1-1)
f(1) = 6.5 miles
f(2) = 6.5 + 1.5(2-1)
f(2) = 6.5 + 1.5
f(2) = 8 miles
Answer: x = -1
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
![4 \frac{1}{2} \div \frac{1}{4} \\ 18](https://tex.z-dn.net/?f=4%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Cdiv%20%20%5Cfrac%7B1%7D%7B4%7D%20%20%5C%5C%2018)
The answer is 0.79. I know it's the answer I am a genius in math.
The answer is 3 you add the two numbers before it