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Gnesinka [82]
3 years ago
6

1.) Evaluate the expression for the given value of the variable. |2x +5|; x = −4

Mathematics
2 answers:
mariarad [96]3 years ago
4 0

Answer:

3

Step-by-step explanation:

zloy xaker [14]3 years ago
3 0

Answer:

3

Step-by-step explanation:

|2(-4)+5| = |-8+5| = |-3|

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Find the missing length in the right triangle.
adoni [48]

Answer:

10 ft

Step-by-step explanation:

By using the pythagorean theorem, we know that leg1 squared plus leg2 squared is equal to hypotenuse squared.

6^2+8^2=?^2\\36+64=?^2\\100=?^2\\10=?

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3 years ago
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A ride sharing service charges $4.25 for every ride, plus $0.30 per mile. If m represents miles, which rule for p(m) models the
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3 years ago
"A passenger train traveled 100 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the fre
Pavel [41]

Answer: the rate of the passenger train is 100 mph.

Step-by-step explanation:

Let x represent the rate of the passenger train.

The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. It means that the rate of the freight train is (x - 10) mph

The passenger train traveled 100 miles. It means that the time it took travel 100 miles is

100/x

In the same amount of time, it took a freight train to travel 90 miles. It means that the time it took travel 90 miles is

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Since the time is the same, then

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Cross multiplying, it becomes

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100x - 1000 = 90x

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7 0
4 years ago
At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37
monitta

Answer:

Half-life of the goo is 49.5 minutes

G(t)= 300e^{-0.014t}

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let M_0\,,\,M_f denotes initial and final mass.

M_0=300\,\,grams\,,\,M_f=37.5\,\,grams

According to exponential decay,

\ln \left ( \frac{M_f}{M_0} \right )=-kt

Here, t denotes time and k denotes decay constant.

\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014

So, half-life of the goo in minutes is calculated as follows:

\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes

Half-life of the goo is 49.5 minutes

\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}

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G(t)= M_f=M_0e^{-kt}

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7 0
3 years ago
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Y=3x-1 have a great day!!
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