How is Demoragan's law used in logic ?

Mathematics

2 answers:

Murrr4er [49]3 years ago

6 0

Answer:

De Morgan's Laws describe how mathematical statements and concepts are related through their opposites. In set theory, De Morgan's Laws relate the intersection and union of sets through complements. In propositional logic, De Morgan's Laws relate conjunctions and disjunctions of propositions through negation.

Mekhanik [1.2K]3 years ago

4 0

Answer:

Step-by-step explanation:

In propositional logic and Boolean algebra, De Morgan's laws are a pair of transformation rules that are both valid rules of inference. ... The rules allow the expression of conjunctions and disjunctions purely in terms of each other via negation.

You might be interested in

A population of caribou in a forest grows at a rate of 2% every year. If there are currently 273 caribou, which function represe

Feliz [49]

Answer:

Step-by-step explanation:

C (t)= 273 (0.02)t

6 0

3 years ago

1) A water park charges $5 for entry into the park and an additional $2 for each of the big waterslides. Steven spent $17 on his

777dan777 [17]

1.) The answer is A. 5+2x = 17. The x in the equation signifies the number of times Steven went to the big slides. The 5 represents the fixed cost of the slide. The total expenditure in the water park is 17 dollars, and the 2 represents the cost of using 1 big slide.

2.) The answer is still letter A. 5 +2x =17.

8 0

3 years ago

Can you please help me with this problem

vagabundo [1.1K]

$\bf \begin{cases}
\textit{area of a circle}=\pi r^2
\\ \quad \\
circumference=2\pi r
\end{cases}
\\ \quad \\

12.56=\pi r^2\implies \cfrac{12.56}{\pi }=r^2\implies \sqrt{\cfrac{12.56}{\pi }}=\boxed{r}
\\ \quad \\
thus
\\ \quad \\
circumference=2\pi \boxed{r}\implies 2\pi \boxed{\sqrt{\cfrac{12.56}{\pi }}}$

8 0

3 years ago

Kyle bought a ticket to see his favorite basketball team playing at home. His seat is in the terrace section, about 178 feet fro

maw [93]

Answer:

128.6

Step-by-step explanation:

I just did the math

3 0

2 years ago

How do I solve this problem

Vaselesa [24]

C = 84 degrees

A = 2B
C = A + 20
A + B + C = 180

A = 2B
A/2 = B

A + (A/2) + (A+20) = 180
multiply each side by 2
2A + A + 2A + 40 = 360
combine like terms
5A + 40 = 360
subtract 40 from both sides
5A = 320
divide both sides by 5
A = 64

C = A + 20
C = 64 + 20
C = 84

4 0

2 years ago