All categories

3 years ago

Help me please help.

Mathematics

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

steps below

Step-by-step explanation:

This is a contradictory proof of sophistry

f(x+4) = f(x)+f(4) ...(1) when x=0

f(x+4) = f(0+4) = f(4) = f(x) + f(4)

f(x) = f(4)-f(4) = 0

From (1): f(x) = f(x+4) - f(4)

x=-4 f(-4) = f(-4+4) - f(4) = f(0) - f(4) = -f(4) ...(2)

From (1): f(x+4) = f(x)+f(4)

x=4 f(4+4) = f(8) = f(4) + f(4) = 2f(4) = -2f(-4) from (2) ... (3)

f(8) +2f(-4) = -2f(-4) + 2f(-4) = 0

You might be interested in

True or False, An integer divided by its opposite allways equals -1. This is false because of "0" is this correct?

valentinak56 [21]

An integer divided by its opposite always equals -1: this is false. Any number which is not 0 divided by it's opposite is in fact equal to -1, but since 0 is also an integer, it's false. You are right, good job!

4 0

2 years ago

Read 2 more answers

7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and A = {6, 10, 14}, what is A'?

Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

Learn more about sets here:

brainly.com/question/2166579

#SPJ9

5 0

9 months ago

Multiply.

Crank

The main rules that we use here are :

i) $\sqrt{a \cdot b}= \sqrt{a} \cdot \sqrt{b}$ for nonnegative values a and b.

ii) $\sqrt{a} \cdot \sqrt{a} =a$ .

Thus, first 'decompose' the numbers in the radicals into prime factors:

$4 \sqrt{3} \cdot 10 \cdot \sqrt{2\cdot2\cdot3}\cdot \sqrt{2\cdot 3}\cdot \sqrt{2}.$ .

By rule (i) we write:

$4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot \sqrt{3} \cdot \sqrt{2}$ .

We can collect these terms as follows:

$40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2})$ , and by rule (ii) we have:

$40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.$

Answer: $480 \sqrt{3}$ .

8 0

3 years ago

Help algebra 2 please

kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

= x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

= x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

= -5x³ + 2x² + 7x - 5x² + 2x + 7

= - 5x³ + 2x² -5x² + 7x + 2x +7 {Combine like terms}

= -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

= x*(x² + 2x + 4) - 2*(x² + 2x + 4)

= x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

= x³ + 2x² + 4x -2x² -4x - 8

= x³ - 8

$2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}$

$1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}$

7 0

3 years ago

Products of equal value totaling $480 are sold to an audience of an unknown amount of people. the entrance fee is $10 per person

Sholpan [36]

Y = $\frac{10x+480}{x}$

This is because the total cost is 10x + 480 and then that needs to be divided by the amount of people.

8 0

3 years ago

Help me please help. ​

Help me please help.