Answer:
(a) 46°
(b) 86°
Step-by-step explanation:
When the secants cross externally (figure a), the angle where they cross is half the difference of the subtended arcs.
When they cross internally (figure b), the angle is half the sum of the subtended arcs.
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<h3>(a)</h3>
Half the difference of arcs VW and VX is ...
∠VYW = 1/2(160° -68°) = 46°
m∠VYW = 46°
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<h3>(b)</h3>
Half the sum of arcs AB and CD is ...
∠CED = 1/2(arc AB +arc CD)
2×∠CED = arc AB +arc CD . . . . . multiply by 2
2×∠CED -arc AB = arc CD . . . . . subtract arc AB
arc CD = 2×85° -84° = 86°
m arc CD = 86°
Answer
(4x-5) = -20 (2x+8) = 2
Step-by-step explanation:
2 x − 8 = 2 2x-8=2 2x−8=2. Add 8 to both sides. Simplify 2 + 8 2+8 2+8 to 10. Divide both sides by 2. If its wrong then I’m very sorry but I’m sure this is correct.
The formula for the surface area is given and as follows.
SA = (2)(3.14)(r^2) + (2)(3.14)(r)(h)
The radius of the cylinder is 4 inches and the height is 9 inches. Using the given values, we can plug them into the formula and solve for the surface area from there.
SA = (2)(3.14)(4^2) + (2)(3.14)(4)(9)
SA = (6.28)(16) + (6.28)(36)
SA = 100.48 + 226.08
SA = 326.56 in^2
Hope this helps!! :)
The correct answer: 7.428 inches
Explanation:
Given the equation is D(r) = 0.145r^2
Where D is the depth and r is the radius
Putting D = 8 inches in the equation
8 = 55.2
r^2= 8/ 0.145
r^2 = 55.2
R^2= 7.428 inches
The radius of depth is 7.428 inche
Hope this help you : )
