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Semmy [17]
3 years ago
12

Find a quadratic function that includes the set of values below.

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

9514 1404 393

Answer:

  y = -2x^2 +7x +4

Step-by-step explanation:

A graphing calculator or spreadsheet can tell you the quadratic regression formula that will fit these points:

  y = -2x^2 +7x +4

__

If you'd like to do this "by hand", you can substitute the given points into the equation y = ax^2 +bx +c to get three linear equations in a, b, c.

  4 = 0 +0 +c

  10 = a(2^2) +b(2) +c

  0 = a(4^2) +b(4) +c

Using the value of c from the first equation, these reduce to ...

  6 = 4a +2b

  -4 = 16a +4b

Dividing the second of these equations by 2, and subtracting the first, we have ...

  (16a +4b)/2 -(4a +2b) = (-4)/2 -(6)

  4a = -8

  a = -2

From the first of the reduced equations, we find ...

  b = (6 -4a)/2 = 3 -2a = 3 -2(-2) = 7

So, a=-2, b=7, c=4, and the equation is ...

  y = -2x^2 +7x +4

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nikitadnepr [17]
The value of 7 is 0.007
4 0
4 years ago
A car dealership finds that a certain model of new car has something wrong with its transmission 15% of the time. How likely is
victus00 [196]

Answer:

Unlikely, the probability is close to 0

Step-by-step explanation:

Given

Transmission = 15\%

Required

Determine the likelihood

The given probability, 0.15 is close to 0. This implies that the event is unlikely.

From the list of given options, option C answers the question

4 0
4 years ago
Which equation is a point slope form equation for line AB?
sukhopar [10]

Answer:

option 1

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = A(1, 6) and (x₂, y₂ ) = B(5, - 2)

m = \frac{-2-6}{5-1} = \frac{-8}{4} = - 2

Use either of the 2 points for (a, b)

Using (a, b) = (5, - 2) , then

y - (- 2) = - 2(x - 5) , that is

y + 2 = - 2(x - 5)

3 0
4 years ago
Graph the relation and tell whether it is a function (1,3) (2,3) (-1,4) (|-1), (-3,2)
kramer

Answer:

no

Step-by-step explanation: does not pass the vertical line test

3 0
3 years ago
Write a polynomial function of least degree with integral coefficients that has the given zeros. -5, 3i
Virty [35]

Solving for the polynomial function of least degree with integral coefficients whose zeros are -5, 3i

 

We have:
x = -5

Then x + 5 = 0

Therefore one of the factors of the polynomial function is (x + 5)


Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0

Therefore one of the factors of the polynomial function is (x^2 + 9)


The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)

= x^3 + 9x + 5x^2 = 45

Therefore, x^3 + 5x^2 + 9x – 45 = 0

f(x) = x^3 + 5x^2 + 9x – 45

 

The polynomial function of least degree with integral coefficients that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45

5 0
3 years ago
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