Question

Find an equation of the line with the given properties parallel to y=-1/3x-2 containing the pt (6,-10)

Answer 1

Answer:

y + 10 = -1/3 (x - 6) OR y = -1/3x-8

Step-by-step explanation:

take the slope of y = -1/3x - 2 (the slope is -1/3)

plug the slope and the point into this equation: y - y1 = m (x - x1)

m represents your slope, y1 and x1 represnt your points so just plug in

so y + 10 = -1/3 (x - 6) or y = -1/3x-8 (subtract 10 from both sides and distribute the -1/3 to (x -6)).