Step-by-step explanation:
The area that cow can graze is in the form of semicircle.
Radius of semicircle
Length of rope =14 m
Required area = 1/2 ×πr
=1/2×22/7×r^2
=1/2×22/7×14×14
=308m2
Answer:
-1.28
Step-by-step explanation:
You would put these two equations into a graphing ccalculator:
y = -4x - 1
and
y= 5^x + 4
Wherver they intersect is your answer.
These two happen to intersect at (-1.28,4.13)
Since the equation has x-values, you would give the first number (x-coordinate) as your answer.
Answer: 24 units.
Step-by-step explanation: Count out how many units long AB is. AB goes from -3 to 3, for a length of 6 units.
Count out how long AC is. AC goes from 4 to -4, for a length of 8 units.
To find BC, use the Pythgorean theorem (a^2+b^2=c^2). 8^2 is 64, and 6^2 is 36. Add 64 and 36 to get 100. Then find the square root of 100, which is 10.
Add all the lengths. 6+8+10=24.
Answer:
Meee :)
Step-by-step explanation:
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