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viva [34]
3 years ago
9

What is the distance between (-2,-2) and (4,4)

Mathematics
1 answer:
Bogdan [553]3 years ago
5 0
<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

6\sqrt{2} or 8.485

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

Given:

(-2,-2)

(4,4)

Solving for the Distance:

\sqrt{(-2-4)^2 +(-2 -4)^2} \\ \sqrt{(-6)^2 +(-6)^2} \\ \sqrt{36 +36} \\ \sqrt{72} \\ \sqrt{36 \cdot 2} \\ 6 \sqrt{2}

<u>Note:</u>

6 \sqrt{2} \approx 8.485

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Verification:

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88168in²

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4 years ago
A large wooden box, as shown, has a volume of 4352 ft3. The box is a right square prism with a base with sides that each measure
notsponge [240]
<h2>Volume of a Prism</h2>

To find the volume of a prism, we can use the following formula:

V=base\hspace{3}area*height

Although this formula is typically used to find the volume of a prism, we can also use it to find the base area or height, as long as we re-arrange it accordingly.

For a rectangular prism, the base area is solved using the following formula:

A=lw ⇒ where <em>l</em> is the length and <em>w</em> is the width

<h2>Solving the Question</h2>

We're given:

  • V = 4352 ft³
  • <em>l</em> = 16 ft
  • <em>w</em> = 16 ft
  • We need to solve for the height of the box.

First, find the base area:

A=lw\\A=16^2\\A=256

Therefore, the base area is equal to 256 ft².

Now, modify the volume formula to isolate the height:

V=base\hspace{3}area*height

⇒ Divide both sides by the base area:

\dfrac{V}{base\hspace{3}area}=\dfrac{base\hspace{3}area*height}{base\hspace{3}area}\\\\\dfrac{V}{base\hspace{3}area}=height\\\\height=\dfrac{V}{base\hspace{3}area}

⇒ Plug in the given values:

height=\dfrac{4352}{256}\\\\height=17

Therefore, the height of the box is 17 ft.

<h2>Answer</h2>

The height of the box is 17 ft.

3 0
2 years ago
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<h2>{\bold {\pink {\underbrace {\red {\sf {\overbrace {\orange {Answer\:Grade\:5}}}}}}}}</h2>

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。。。。。。。。。。。。。。。。。。。。。。。。。。。。

\:

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