The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
I would do 3+5 so then it equals 8
M1= -5 , m2 = 5 inorder to get this you move the constant to the right take the root of both sides separate the solutions and you should get m1= -5, m2 =5
Step-by-step explanation:
100% = 96
1% = 100%/100 = 96/100 = 0.96
the temperature changed by 96 - 71 = 25.
how many % are these 25 ?
we check how often 1% fits into 25.
that is done by division :
25 / 0.96 = 26.04166667 ≈ 26%
Answer:
a. 5
Step-by-step explanation:
arrange
1 2 3 5 5 6 6 6 8 9 9 10 10 11 12 13
median=6+8/2=7
range=13-1=12
difference=12-7=5
please mark as brainliest
