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2 years ago

James is 105 pounds. His coach

1 answer:

8 0

You have to do 12 times 4, which equals 48. So 48 pounds in a year. 105 plus 48 would be 153 so that would be his weight by next year

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2,5, 25/2, ... find the 10th term

notka56 [123]

Answer:

The $10^{th}$ term of the given sequence

$t_{10} = \frac{5^{9} }{2^{8} }$

Step-by-step explanation:

Step(i):-

Given sequence 2 , 5, $\frac{25}{2}$

First term a = 2

The difference of given geometric sequence

$d = \frac{r_{2} }{r_{1} } = \frac{5}{2}$

Step(ii):-

The $n^{th}$ term of the given sequence

$t_{n} = ar^{n-1}$

The $10^{th}$ term of the given sequence

$t_{10} = (2)(\frac{5}{2} )^{10-1}$

$t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }$

8 0

3 years ago

Experimentally verify sum of three angles of an triangle is 180⁰.

svetlana [45]

Draw line a through points A and B. Draw line b through point C and parallel to line a.

Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.

It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.

Thus <)ABC + <)BCA + <)CAB = 180 degrees.

Lemma

If ABCD is a quadrilateral and <)CAB = <)DCA then AB and DC are parallel.

Proof

Assume to the contrary that AB and DC are not parallel.

Draw a line trough A and B and draw a line trough D and C.

These lines are not parallel so they cross at one point. Call this point E.

Notice that <)AEC is greater than 0.

Since <)CAB = <)DCA, <)CAE + <)ACE = 180 degrees.

Hence <)AEC + <)CAE + <)ACE is greater than 180 degrees.

Contradiction. This completes the proof.

Definition

Two Triangles ABC and A'B'C' are congruent if and only if

|AB| = |A'B'|, |AC| = |A'C'|, |BC| = |B'C'| and,

<)ABC = <)A'B'C', <)BCA = <)B'C'A', <)CAB = <)C'A'B'.

4 0

2 years ago

three students had $9.00 total and went to a smack bar where their bill was $6.57. they want to divide up the money that is left

KatRina [158]

9.00+6.57=× is the answer

3 0

2 years ago

Which expression is equivalent to m^2-13m-30?

sergiy2304 [10]

Answer: First option

Step-by-step explanation:

You have the quadratic equation given in the problem:

$m^2-13m-30$

To find an equivalent expression you cacn factorize. Find two numbers whose sum is -13 and whose product is -30.

These numbers would be -15 and 2.

Therfore, you obtain the following equivalent expression:

$(m-15)(m+2)$

If you don't want to apply the method above, you can use the quadratic formula:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

Where:

$a=1\\b=-13\\c=-30$

When you susbstitute values you obtain that:

$x=15\\x=-2$

Then you can rewrite the equation as $(m-15)(m+2)$

7 0

2 years ago

Read 2 more answers

Does the square root of a rational number have to come out as a rational number?

AlekseyPX

Answer:

no it does not have to

Step-by-step explanation:

4 0

2 years ago