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siniylev [52]
2 years ago
12

What would be the simplified expression AFTER the first step in this expression: 10–5+3×9÷3

Mathematics
1 answer:
dmitriy555 [2]2 years ago
6 0

Answer:

10-5+3×3

Step-by-step explanation:

that what you get when you first work out the division sign

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

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3 years ago
Simplify the radical expression
Keith_Richards [23]

Answer:

how can someone solve dis?

Step-by-step explanation:

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3 years ago
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It's a quotient identity
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3 years ago
Subtract. –5.8 – (–8.4) A. –14.2 B. –2.6 C. 2.6 D. 14.2
svp [43]
-5.8 - (-8.4)

When we multiply two negatives they become a positive. In this situation, where there is no other number, you can assume there's basically a 1 in that place. 

-5.8 - 1(-8.4) would be just as correct. (If this helps visually clarify anything.)

So we take that -1 and multiply it by that -8.4. Multiplying 1 against anything leaves it the same, so we just need to change the sign. Two negatives make a positive. 

-5.8 + 8.4

Now we add these together.

This gives us our final answer of 2.6
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Nadusha1986 [10]
180/3x then you get you answer 

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