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Juliette [100K]
3 years ago
10

Solve the following problem. 5/6−1/8=

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

Answer:

Exact Form: 17/24

Decimal Form: 0.7083 **repeating**

Step-by-step explanation:

//Give thanks(and or Brainliest) if helpful (≧▽≦)//

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Max lost 23 pounds while on a diet. He
san4es73 [151]
184+23=w
207=w
That’s the answer 207
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3 years ago
The easiest way to find THE SLOPE on a graph? Please HELP
ratelena [41]

Step-by-step explanation:

Pick two points on the line and determine their coordinates

Select one to be (x1, y1) and the other to be (x2, y2)

Finally use the slope intersect equation to calculate the slope:

<em>Formula-</em><em> </em>

<em>y = mx + b </em>

<em></em>

Hope this helps, let me know if you need more information, I'll be glad to help! :)

3 0
3 years ago
The length of time required for the periodic maintenance of an automobile or another machine usually has a mound-shaped probabil
maks197457 [2]

Solution :

Mean time for an automobile to run a 5000 mile check and service = 1.4 hours

Standard deviation = 0.7 hours

Maximum average service time = 1.6 hours for one automobile

The z - score for 1.6 hours = $\frac{1.6-1.4}{0.7 / \sqrt{50}}$

                                           = 2.02

Now checking a normal curve table the percentage of z score over 2.02 is 0.0217

Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.

8 0
3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
The equation of line EF is y = 1 over 2 x + 6. Write an equation of a line parallel to line EF in slope-intercept form that cont
MrRissso [65]
Nor sure what you're doing on the bottom but use point slope thing
y-0=-2(x+2)
y=-2x+2
So not sure what you're asking but...
yeah, you're right.
5 0
3 years ago
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