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Phoenix [80]
4 years ago
15

A rescue helicopter is used to help victims who fell in a ditch. The helicopter begins at sea level, which is an elevation of 0

feet. It then travels down for 100 seconds at a speed of 10.5 feet per second. It then travels directly up for 150 seconds at a speed of 5.2 feet per second. After this 250 second period, how much time, in seconds, will it take for the rescue helicopter to travel back to sea level at the helicopter's maximum speed of 15.8 feet per second?
Mathematics
1 answer:
cupoosta [38]4 years ago
3 0

Answer:

The helicopter still needs to fly up sec 17.0886 at maximum speed.

Step-by-step explanation:

To find out how far the helicopter went down do 100(seconds) * 10.5 and get 1050

Then how much he traveled back up same thing 150 (seconds) * 5.2 and get 780

Next  find the difference 780-1050 and get -270 ft it is negative because it is still BELOW GROUND ( That's how you know if it need to fly up or down)

Last to find how many seconds you need you work backwards so instead of multiplying you do the opposite witch is dividing so you take your feet (270) and divide by the maximum speed (15.8). 270/15.8 is 17.08

 



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7 pt 1 c + 4 pt 1 c
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ANSWERS

1. B

2. B

3. A

4. C
5. B

6. A

 

WORKINGS

 

QUESTION 1

7 pt 1c + 4pt 1c (pt for Pints; c for Cups)
= 7pt + 1c + 4pt + 1c

 

Collecting like terms

= 7pt + 4pt + 1c + 1c

= 11pt + 2c

 

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Therefore,

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QUESTION 2

7c 3fl oz – 3c 4fl oz (c for Cups; oz for Ounce)
= 7c + 3fl oz – (3c + 4fl oz)

= 7c + 3fl oz – 3c – 4fl oz

 

Collecting like terms

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Therefore, 4c can be rewritten as 3c + 8fl oz

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= 3c + 7fl oz

= 3c 7fl oz (Option B)

 

 

QUESTION 3

4lb 4oz – 2lb 7oz (lb for Pounds; oz for Ounce)

= 4lb + 4oz – (2lb + 7oz)

= 4lb + 4oz – 2lb – 7oz

 

Collecting like terms

= 4lb – 2lb + 4oz – 7oz

= 2lb – 3oz

 

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Therefore, 2lb can be rewritten as 1lb + 16oz

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QUESTION 4

7T 200lb – 2T 700lb (T for Tons; lb for Pounds)

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