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natali 33 [55]
3 years ago
8

2+8888888888+99999999999=

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

108888888889

Step-by-step explanation:

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Solve for s in the proportion.<br> s=<br> Submit<br> 40/30=8/s
vitfil [10]

Answer:

s =6

Step-by-step explanation:

40            8

--------- = ---------

30            s

Using cross products

40*s = 30*8

40s = 240

Divide each side by 40

40s/40 = 240/40

s = 6

4 0
3 years ago
Which shows like terms from the expression? 9 + 5 + 7x2 + 3 x2y + 2x2 3 x2y and 2x2 7x2, 3 x2y, and 2x2 9 and 5 2, 3, 5, and 9
snow_lady [41]

Answer:

9 and 5.

Step-by-step explanation:

So we have the expression:

9+5+7x^2+3x^2y+2x^2

In order to combine like terms, the variables must be <em>exactly</em> the same: not one less, not one more.

3x²y and 2x² <em>cannot</em> be combined because the first value has a y.

7x², 3x²y, and 2x² also <em>cannot </em>be combined because the second value has a y.

9 and 5 is the only one that can be combined because they are just integers. They can be added to be 14.

2, 3, 5, and 9 <em>cannot</em> be combined because the 2 and the 3 are tied to the variables as coefficients. They are not constants.

5 0
3 years ago
Read 2 more answers
Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am
Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

6 0
3 years ago
Hey cylindrical water tank is being filled with the hose. The depth of the water increases by 1 1/4 ft./h how many hours will it
irakobra [83]
First off, let's convert the mixed fractions to "improper", keeping in mind that the water is increasing every passing hour by 1 and 1/4.

\bf \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}}&#10;\\\\\\&#10;\stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}}\\\\&#10;-------------------------------

\bf \begin{array}{ccll}&#10;feet&hours\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{5}{4}&1\\\\&#10;\frac{7}{2}&h&#10;\end{array}\implies \cfrac{\quad \frac{5}{4}\quad }{\frac{7}{2}}=\cfrac{1}{h}\implies \cfrac{5}{4}\cdot \cfrac{2}{7}=\cfrac{1}{h}\implies \cfrac{5}{2}\cdot \cfrac{1}{7}=\cfrac{1}{h}&#10;\\\\\\&#10;\cfrac{5}{14}=\cfrac{1}{h}\implies h=\cfrac{14\cdot 1}{5}\implies h=\cfrac{14}{5}\implies h=2\frac{4}{5}
3 0
3 years ago
Jim drives at a speed of 50 miles per hour. How long will it take to drive 125 miles?​
antoniya [11.8K]
Answer: 2 hrs and 30 mins

Explanation:

125/150 = 5/2

5/2 = 2.5
4 0
3 years ago
Read 2 more answers
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