37) Kali ran 17 miles less than Alberto last

Write one number that is a factor 13.

andreyandreev [35.5K]

Answer:

1

Step-by-step explanation:

This is because 13 is a primary number

3 0

3 years ago

4x = 8x − 1 x = three fourths x = 1 x = 3 x = 6

makvit [3.9K]

Isolate the variable by subtracting 8x from both sides to get -4x = -1. multiply both sides by -1 to get 4x = 1. divide both sides by 4 to get x = 1/4.

5 0

3 years ago

Read 2 more answers

Let $a$, $b$, $c$, $d$, and $e$ be positive integers. The sum of the four numbers on each of the five segments connecting "point

kiruha [24]

Answer:

i dunno

Step-by-step explanation:

somebody help

6 0

4 years ago

Use a number line to order the numbers from least to greatest. 39 33.6. 61

Kipish [7]

Answer:

33.6, 39, 61. That's without knowing these numbers

8 0

3 years ago

Read 2 more answers

7. Sky Castle Company is conducting research on 3 independent communities of 12 members each to see how they have been consuming

tresset_1 [31]

Answer:

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

Step-by-step explanation:

To solve this question, we need to use two separate binomial trials.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least 11 members being categorized as low risk participants.

12 members in the sample, so $n = 12$

30% chance to be categorized as high risk participants. So 100-30 = 70% probability of being categorized as low risk participants. So $p = 0.7$

This probability is

$P(X \leq 11) = P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{12,11}.(0.7)^{11}.(0.3)^{1} = 0.0712$

$P(X = 2) = C_{12,12}.(0.7)^{12}.(0.3)^{0} = 0.0138$

$P(X \leq 11) = P(X = 11) + P(X = 12) = 0.0712 + 0.0138 = 0.0850$

What is the probability that at least 11 members are categorized as low risk participants in two of three communities?

For each community, 8.50% probability of at least 11 members being categorized as low risk. So $p = 0.085$

Three comunities, so $n = 3$

This probability is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.085)^{2}.(0.915)^{1} = 0.0198$

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

6 0

4 years ago