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3 years ago

Rachel earned 164 babysitting last month she earned 95 this month Rachel rounded each amount

Mathematics

2 answers:

Marina86 [1]3 years ago

7 0

Answer:

100+170= 270 round 164 and 95 to the nearest 10th

Step-by-step explanation:

You are welcome may I please get brainliest?:)

Lesechka [4]3 years ago

5 0

Answer:

$260

Step-by-step explanation:

164 to the nearest tenth is 160 then 95 to the nearest tenth is 100 so then you have to add 100 and 160 together to get $260.

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If a laptop originally costs $800, the balance due after the 10% discount and $150 gift card is applied is

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The answer is 570$
10% of 800 is 80 + 150$ is 230
800-230=570

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Eric and mark went t a ball game and visited the concession stand.They each got a hot dog,and mark got a large soda and a bag of

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The soda was $1.00.

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A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

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3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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