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3 years ago

Pls Help, Me give Brainliest plllllssssss I offer 56 points ppppppppppppppppplllllllllllllllsssssssssssssssss

Mathematics

1 answer:

timurjin [86]3 years ago

4 0

Answer:

I can't see the map!!!

Step-by-step explanation:

please post again but with less points

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Simplified form of expression 125 2/3

masha68 [24]

Answer:

377/3

Step-by-step explanation:

In general if we have a fraction ( mixed) as ,

$a\dfrac{c}{d}$

Then the improper fraction will be ,

Improper fraction :-

$\dfrac{ d\times a + c}{d}$

Using this concept we have ,

→ 125 ⅔

→ 125 × 3 + 2 / 3

→ 375 + 2/3

→ 377/3

<h3>Hence the simplified form of the expression is 377/3 .</h3>

3 0

3 years ago

Name the set(s) of numbers which belong to -1/2 belongs

OLEGan [10]

Answer:

2 rational number because it's negative it can't be natural and cuz it's fraction it can't be whole nor integers

4 0

3 years ago

Read 2 more answers

A)Loss is denoted by a negative integer and profit is denoted by a positive integer. A

Rashid [163]

Answer:

750 profit

Step-by-step explanation:

Given :

Profit of 10 on white cement

Loss of 5 on Grey cement

Number of white cement sold = 325 bags

Number of Grey cement sold = 500 bags

Total profit made on sale of white cement :

10 * 325 = 3250

Loss made on sale of Grey cement :

5 * 500 = 2500

Total profit or loss :

3250 - 2500

= 750

Profit value is greater than. Loss value (hence, total profit of 750 was made).

6 0

3 years ago

How much has the value of y changed between the points (–8, 4) and (8, –4)?

Klio2033 [76]

The y value has changed by 8

6 0

4 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago