Amount of Interest=7152-6400=752=I
- Principal=6400=P
- Rate of interest=6%=R
- Time=T=?
We know
1000₂<x₁₀<10000₂ = 1,000,000<x₁₀<100,000,000 reading one million is less than x₁₀, and x₁₀ is less than 100,000,000.
Here is each answer for x₁₀:
7= 282,475,249
8= 1,073,741,824
15= 576,650,390,625
16= 1,099,511,627,776
With those numbers, it doesn't look like any answer is right. I am thinking I am not understanding the question....
54x+14= 43x+36
54x-43x= 36-14
11x = 22 /11
X =2
54*2+14 -= 122
Both the same
And the other are 180-122 = 58
Answer:
$18,413.01
Step-by-step explanation:
Use the formula for interest compounded continuously:
A = Pe^(rt)
where P is the principal invested ($14,000), r is the annual interest rate (.0685), and t is the number of years (4).
A = $14,000·e^(.0685·4) = $14,000·e^0.274
A ≈ $18,413.01
If x is the average of "the other 20 numbers", then their sum is 20x. Adding the 21st number makes the sum of all 21 numbers be 20x +4x = 24x.
The 21st number, 4x, is 4x/(24x) = 1/6 of the total of all numbers,