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Wewaii [24]
3 years ago
9

The average red

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0

The question is an illustration of ratios and proportions

<em>The Bospolder fox is 28 inches tall at the shoulder,</em>

Represent the ratio as:

Scale = Shoulder : Tail

For the red fox, we have:

Red = 20in : 55in

For the Bospolder fox, we have:

Bospolder =Shoulder : Tail

To calculate the length of the shoulder of the Bospolder fox, we need its length at the tail.

<em>Since it is not given, I will make an assumption.</em>

Assume, the Bospolder fox is 77in tall at the tail.

The ratio becomes

Bospolder =Shoulder : 77in

Both animals are proportional; this means that they have the same ratio.

So, we have:

Shoulder : 77in = 20in : 55in

Express as fraction

\frac{Shoulder }{ 77in }= \frac{20in }{55in}

Multiply both sides by 77in

Shoulder = \frac{20in }{55in} \times 77in

Shoulder = \frac{20in \times 77}{55}

Shoulder = 28in

Using the assumed length, the Bospolder fox is 28 inches tall at the shoulder,

Read more about ratios and proportions at:

brainly.com/question/13114933

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At the school cafeteria, each student who ordered lunch gets 6 chicken nuggets. The cafeteria staff prepares enough for 300 kids
lesya [120]
1800.... 300 students x 6 nuggets per student= 1800 total :)
4 0
3 years ago
You take out a student loan for $80,000 with 2.75% annual interest to pay for your first year of college. This loan will cover a
yKpoI14uk [10]

Exponential growth equation would be

Amount= 80,000 (1+2.75/100) ⁴

At the end of 4 years I would have to repay an amount of $ 89,169.70

Step-by-step explanation:

Since, the amount is loaned it would vary exponentially i.e. in a compounding manner.

We know that for compound interest, the equation is written as-

Amount= principal(1+r/100) ˣ

Where r- rate of interest which is 2.75% annually

And x= time period= 4 years as in the question

Principal= $ 80,000

Therefore, Equation becomes-

Amount= 80,000(1+2.75/100) ⁴

On solving this Amount would equal $ 89,169.70

Hence, at the end of 4 years I would have to repay an amount of $ 89,169.70.

6 0
3 years ago
What adds up to -54 and multiplies to -16
Kaylis [27]
X + y = -54
xy = -16

xy = -16
\frac{xy}{x} = \frac[-16}{x}
y = \frac{-16}{x}

x + y = -54
x + \frac{-16}{x} = -54
\frac{x^{2}}{x} + \frac{-16}{x} = -54
\frac{x^{2} - 16}{x} = -54
x^{2} - 16 = -54x
x^{2} + 54x - 16 = 0
x = \frac{-(54) \± \sqrt{(54)^{2} - 4(1)(-16)}}{2(1)}
x = \frac{-54 \± \sqrt{2916 + 64}}{2}
x = \frac{-54 \± \sqrt{2980}}{2}
x = \frac{-54 \± 59.6}{2}
x = -27 \± 29.8
x = -27 + 29.8    or    x = -27 - 29.8
x = 2.8    or    x = 56.8

     x + y = -54
  2.8 + y = -54
- 2.8          - 2.8
           y = -56.8
     (x, y) = (2.8, -56.8)

             or

        x + y = -54
  -56.8 + y = -54
+ 56.8        + 56.8
              y = 2.8
        (x, y) = (-56.8, 2.8)

The two numbers that add up to -54 and multiply to -16 are -56.8 and 2.8.
8 0
3 years ago
Please answer quickly
miskamm [114]

Answer:

MN=4

Step-by-step explanation:

LM+MN=LN

4x+2+3x-5=5x+3

7x-5x=3+3

2x=6

x=3

MN=3x-5

MN=9-5=4

MN=4

4 0
3 years ago
What is the p-value? -- Researcher Jessie is studying how the fear of going to the dentist affects an adult's actual number of v
Vesnalui [34]

Answer:

Two, one for the 14 responses (number of visits) by the adults who fear going to the dentist and one for the 31 responses (number of visits) by the adults who do not fear going to the dentist.

Step-by-step explanation:

Hello!

1)

You want to test if the average visits to the dentist of people who fear to visit it are greater than the average visits of people that don't fear it.

In this case, the statistic to use is a pooled Student t-test. The reason I've to choose this test is that one of your sample sizes is small (n₁= 14) and the t-test is more accurate for small samples. Even if the second sample is greater than 30, if both variables are normally distributed, the pooled t-test is the one to use.

H₀: μ₁ = μ₂

H₁: μ₁ > μ₂

α: 0.10

t=<u> (X₁[bar]-X₂[bar]) - (μ₁ - μ₂)</u> ~ t_{n₁+n₂-2}

        Sₐ√(1/n₁+1/n₂)

Where

X₁[bar] and X₂[bar] are the sample means of both groups

Sₐ is the pooled standard deviation

This is a one-tailed test, you will reject the null hypothesis to big numbers of t. Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis), and in this case, is also one-tailed.

P(t_{n₁+n₂-2} ≥ t_{H0}) = 1 - P(t_{n₁+n₂-2} < t_{H0})

Where t_{H0} is the value of the calculated statistic.

Since you didn't copy the data of both samples, I cannot calculate it.

2)

Well there was one sample taken and separated in two following the criteria "fears the dentist" and "doesn't fear the dentist" making two different samples, so this is a test for two independent samples. To check if both variables are normally distributed you need to make two QQplots.

I hope it helps!

3 0
4 years ago
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