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Helga [31]
2 years ago
9

Find the horizontal and vertical intercepts for

Mathematics
1 answer:
allsm [11]2 years ago
3 0

Here, we are required to find the vertical and horizontal intercepts for r⁴ + s² − r s = 16.

The vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.

According to the question;

  • the r-axis is the horizontal axis.
  • the s-axis is the vertical axis.

Therefore, to get the horizontal intercepts, r we set the vertical axis, s to zero(0).

  • i.e s = 0
  • the equation r⁴ + s² − r s = 16, then becomes;
  • r⁴ = 16
  • Therefore, r = ±2.

Also, to to get the vertical intercepts, s we set the horizontal axis, r to zero(0).

  • i.e r = 0.
  • the equation r⁴ + s² − r s = 16, then becomes;
  • s² = 16.
  • Therefore, s = ±4.

Therefore, the vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.

Read more:

brainly.com/question/18466425

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Last year, 31 2 acres of strawberry fields produced approximately 14,700 pounds of strawberries. This year the number of acres p
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So in 5 acres of land produces 21,000 pounds of strawberries.

Step-by-step explanation:

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Last year, 3\frac{1}{2} acres i.e 3.5 acres produced 14,700 pounds of strawberries. So we need to determine how many strawberries were produced per acre.

To do this we divide the total number of strawberries produced by the number of acres it was produced in.

The number of strawberries produced per acre= \frac{14,700}{3.5} = 4,200 pounds.

Step 2:

To determine the number of strawberries in 5 acres of land, we multiply the number of strawberries per acre by the number of acres.

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An important factor in selling a residential property is the number of times real estate, agents show a home. A sample of 21 hom
Natalka [10]

Using the t-distribution to build the 99% confidence interval, it is found that:

  • The margin of error is of 3.64.
  • The 99% confidence interval for the population mean is (19.36, 26.64).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 21 - 1 = 20 df, is t = 2.086.

The other parameters are given as follows:

\overline{x} = 23, s = 8, n = 21

The margin of error is given by:

M = t\frac{s}{\sqrt{n}} = 2.086\frac{8}{\sqrt{21}} = 3.64

Hence the bounds of the interval are:

\overline{x} - M = 23 - 3.64 = 19.36

\overline{x} + M = 23 + 3.64 = 26.64

The 99% confidence interval for the population mean is (19.36, 26.64).

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

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2 years ago
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