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drek231 [11]
3 years ago
12

Write an explicit formula for a_na

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Explicit formula for the sequence 29,20,11....... is a_n=38-9n

Given :

term of the sequence 29, 20, 11, ...

We need to find out the formula for the nth term of the given sequence

Lets find out whether the given sequence is arithmetic or geometric

In the given sequence , common difference is 9

20-29=-9\\11-20=-9

we can say difference =-9

General explicit formula

a_n=a_1+(n-1)d

where a1 is the first term

common difference d=-9

substitute the values

a_n=a_1+(n-1)d\\a_n=29+(n-1)(-9)\\a_n=29-9n+9\\a_n=38-9n

Explicit formula for the sequence 29,20,11....... is a_n=38-9n

Learn more :  brainly.com/question/23243640

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Find the missing value<br> 8<br> 14<br> 45 <br> 15
alekssr [168]

Answer:

The correct option is B.

Step-by-step explanation:

From the given figure it is nices that the length of sides AB, BC and AC are 20, 22 and 35. The line AD is angle bisector.

Let the missing value be x.

The Triangle Angle Bisector Theorem states that the angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle.

Since AD is angle bisector, therefore

\frac{AB}{AC}=\frac{BD}{CD}

\frac{20}{35}=\frac{22-x}{x}

20x=35(22-x)

20x=770-35x

Add 35x both sides.

55x=770

Divide both sides by 55.

x=\frac{770}{55}

x=14

Therefore, second option is correct.

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4 years ago
About % of the area under the curve of the standard normal distribution is between z = − 0.9 z = - 0.9 and z = 0.9 z = 0.9 (or w
prisoha [69]

Using the normal distribution, it is found that 63.18% of the area under the curve of the standard normal distribution is between z = − 0.9 z = - 0.9.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The area within 0.9 standard deviations of the mean is the <u>p-value of Z = 0.9(0.8159) subtracted by the p-value of Z = -0.9(0.1841)</u>, hence:

0.8159 - 0.1841 = 0.6318 = 63.18%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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Answer:

B.

Step-by-step explanation:

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Answer:

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