<span>(a) you can show the concentration by:
amount of salt / amount of water
amount of salt
= 30g / L
= [ 30 * 25g ] / [ 25L ] , 25L = 1 min
= [ 30 * 25g ] / min
amount of water
= 5000 + 25t
[ 30 * 25t ] / [ 5000 + 25t ]
= [ 30 * 25t ] / 25*[ 200 + t ]
= 30t / [ 200 + t ] yeah
(b)
lim t->∞ [ 30t / ( 200 + t ) ]
= lim t->∞ [ ( (1 / t) * 30t ) / ( (1 / t) * ( 200 + t ) ) ]
= lim t->∞ [ 30 / ( (200 / t) + 1 ) ]
= 30 / ( (200 / ∞) + 1 )
= 30 / 1
= 30
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If the square is 15 units on each side, then its diagonal would be √(15²)+(15)²=√450=15√2 ☺☺☺☺
To find invers
1. solve for y
2. replace y with xinverse
so
x=4-4y+y^2
reorder right side
x=y^2-4y+4
factor right side
x=(y-2)^2
squaer root both sides
+/-√x=y-2
add 2 to both sides
2+/-√x=y
switch x and y
2+/-√y=xinverse
xinverse=2+√y or 2-√y
subtract 4 from both sides
Answer:
If you fold it in half.
Step-by-step explanation:
Answer:
From the photo above i interpreted the question and drew a triangle to make it easier to solve
Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)
Tan θ =Opp/Adj
Tan 22°=15/a
Cross Multiply
aTanθ=15°
Divide both sides by Tan 22
aTan22/Tan22 = 15/Tan 22
a = 15/Tan 22°
a = 37.13 m
Therefore the distance between the foot of the cliff to the boat is 37.13 metres