All categories

2 years ago

The product of 6 and the total of z and 9

Mathematics

1 answer:

tatiyna2 years ago

7 0

Answer:

6(z+9)

ANSWER: 6z+54

z=9

Step-by-step explanation:

mm, im sorry they didn't answer this yesterday

You might be interested in

X/1.5 = 4*<br> Help me plz

Anna11 [10]

Answer:

x = 6

Step-by-step explanation:

$\frac{x}{1.5} =4\\\\$

We can multiply both sides by 1.5 to isolate x

$x=4*1.5\\x=6$

4 0

2 years ago

Read 2 more answers

Extra Credit: Graph the function r(x) = |x −5| + 4. Compare the graph to the graph of f(x) = |x|. Describe the domain and range.

Vlad [161]

I forgot. Ill edit this when i remember

3 0

3 years ago

3(x+y)=y

andrew-mc [135]

3(x+y)=y

y is not equal to zero

*Solution

1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis,

3(x+y) = y

3x + 3y = y

Transposing 3y to the right side OR subtracting 3y from both the left-hand side and the right-hand side of the equation would give

3x = -2y

Dividing both sides of the equation by 3,

x = (-2/3)y

Dividing both sides of the equation by y,

x/y = -2/3

Therefore, the ratio x/y has a value of -2/3 provided that y is not equal to zero.

6 0

3 years ago

A photograph is 8 centimeters wide. After Kari enlarges the photograph, it is 3 times as wide as the original. How wide is the p

mr_godi [17]

Answer:24

Step-by-step explanation:Enlarges=multiply ,so multiply 8 and 3

6 0

2 years ago

Read 2 more answers

Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3

yawa3891 [41]

$\bf{1) \ x^4-61x^2+900=0 }$

Applying the factorization method, for example:

$\bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}$

$\bf{\\ &=(x+6)(x-6)(x+5)(x-5); }$

$\bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5 }$

$\bf{2) \ x^4-25x^2+144=0 }$

Applying the factorization method:

$\bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }$

$\bf{ =(x-4)(x+4)(x-3)(x+3); }$

$\bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3 }$

7 0

1 year ago