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2 years ago

The product of 6 and the total of z and 9

Mathematics

1 answer:

tatiyna2 years ago

7 0

Answer:

6(z+9)

ANSWER: 6z+54

z=9

Step-by-step explanation:

mm, im sorry they didn't answer this yesterday

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3/4 pound of Colby cheese costs $1.69. Find the unit price per pound. (3/4 pound=12)

Liula [17]

Answer:

2.25

Step-by-step explanation:

We can write a ratio to solve

1.69 x

------ = ---------------

3/4 lb 1 lb

Using cross products

1.69 * 1 = 3/4 *x

1.69 = 3/4 x

Multiply by 4/3

1.69 * 4/3 = x

x=2.25333

Rounding to the nearest cent

6 0

2 years ago

This is really confusing me:<br> Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$

3 0

3 years ago

The temperature drops 17° to 37° . what was the temperature when we started?

Alex Ar [27]

The temperature would be about 54.

3 0

2 years ago

Read 2 more answers

Which of the following statements is true?

deff fn [24]

Answer:

3/4> 3/5 is true and correct

5 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ehidna [41]

Answer: 1) 0.10

2) 0.60

3) 0.20

4) 0.10

<u>Step-by-step explanation:</u>

The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

$\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]$

6 0

2 years ago