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katovenus [111]
3 years ago
5

3. The graph of a polynomial function is

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

9514 1404 393

Answer:

  A. The degree of the polynomial is even.

Step-by-step explanation:

The end behavior is the same in both directions (for -x and for +x, y → ∞), so the degree of the polynomial is even.

__

The constant term is the y-intercept. It is not an integer, so cannot be said to be even or odd.

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What is 2/6and 3/5 <br> subtracted
pogonyaev

I believe the answer is 4/15.

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3 years ago
A paper bag has 3 red and 7 blue marbles. What is the probability of getting f getting a blue marble on the first try
solong [7]

Answer: 7/10

Step-by-step explanation:

First you add the total number of marbles. Then, you take the total number of blue marbles, and make that your denominator. The total number of marbles is your numerator.

5 0
3 years ago
The time for a visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes
klio [65]

Answer:

a) The mean is 10 and the variance is 0.0625.

b) 0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c) 10.58 minutes.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 10 minutes and a standard deviation of 2 minutes.

This means that \mu = 10, \sigma = 2

Suppose 64 visitors independently view the site.

This means that n = 64,  = \frac{2}{\sqrt{64}} = 0.25

a. The expected value and the variance of the mean time of the visitors.

Using the Central Limit Theorem, mean of 10 and variance of (0.25)^2 = 0.0625.

b. The probability that the mean time of the visitors is within 15 seconds of 10 minutes.

15 seconds = 15/60 = 0.25 minutes, so between 9.75 and 10.25 seconds, which is the p-value of Z when X = 10.25 subtracted by the p-value of Z when X = 9.75.

X = 10.25

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{10.25 - 10}{0.25}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 9.75

Z = \frac{X - \mu}{s}

Z = \frac{9.75 - 10}{0.25}

Z = -1

Z = -1 has a p-value of 0.1587.

0.8413 - 0.1587 = 0.6826.

0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c. The value exceeded by the mean time of the visitors with probability 0.01.

The 100 - 1 = 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{s}

2.327 = \frac{X - 10}{0.25}

X - 10 = 2.327*0.25

X = 10.58

So 10.58 minutes.

6 0
3 years ago
A circle is centered on point BBB. Points AAA, CCC and DDD lie on its circumference. If \orange{\angle ADC}∠ADCstart color #ffa5
tiny-mole [99]

Answer:

  122°

Step-by-step explanation:

The measure of the central angle is twice the measure of the inscribed angle that subtends the same arc.

  ∠ABC = 2×∠ADC = 2×61°

  ∠ABC = 122°

6 0
3 years ago
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Um gato come 5 ratos por dia. Quantos ratos 5 gatos comem em 5dias?​
hram777 [196]

Answer:

1 gato come 5 ratos em 1 dia X 5 = 5 gatos come 25 ratos por dia

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5 0
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