Divide the numerical coefficients and write the quotation in simplest form
Answer:
1.5
Step-by-step explanation:
15/10=1.5
21/14=1.5
Check:
10x1.5=15
Hope this helps!
=3/2+ 9/4+ 2/2
=1.5+ 2.25+ 1
=4.75
Answer:
y = -x -3
Step-by-step explanation:
I went to Desmos and kept guessing y intercepts until the line passed through the point (-4, 1). Sorry I can't explain the real way to figure this out.
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for

the center is (h,k) and the radius is r
and the distance formula is
distance between

and

is

r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so



the radius is

center is (-2,3)
find distance between (8,4) and (-2,3)






≈4.2

≈10.04
do r<D
(8,4) is outside the circle