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3 years ago

Which of the following angles are supplementary to 7? select all that apply.

Mathematics

1 answer:

max2010maxim [7]3 years ago

8 0

Which of the following angles are supplementary to 7? select all that apply.

<u>A. 5</u>

B. 7

C. 6

<u>D. 8</u>

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Find the equation of the line that passes through (-1,3) and is perpendicular to 2y=x−1. Leave your answer in the form y=mx +c A

Lostsunrise [7]

Answer:

y = -2x + 1.

Step-by-step explanation:

2y = x - 1

y = 1/2y - 1/2

If line X is perpendicular to line Y (the line where y = 1/2y - 1/2), the slope will be the negative reciprocal of line Y. That means that there will be a negative sign instead of positive, and the 1/2 will be flipped to become 2/1, which is 2.

So, the slope will be -2.

We now have y = -2x + c.

To find c, simply put in -1 for x and 3 for y.

3 = -2 * -1 + c

c + 2 * 1 = 3

c + 2 = 3

c = 1

So, the equation of the line is y = -2x + 1.

Hope this helps!

8 0

3 years ago

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13. A cone with a radius of 3 inches and a height of 7 inches has the same radius as a cylinder. If the cylinder's volume is two

Ghella [55]

Answer:

Step-by-step explanation:

r = 3 in

h = 7 in

volume of cone = ⅓πr²h = 21π in³

cylinder has radius r = 3 and height h.

volume of cylinder = πr²h = 9πh in³

volume of cylinder is two times the volume of cone

9πh = 2×21π

9h = 42

h = 42/9 = 4⅔ in

3 0

2 years ago

Craig’s school has 4 lessons in the morning lessons 1 starts at 8:35 each lesson is 60 minutes long there is a break between les

jasenka [17]

Answer:

12:50 PM.

Step-by-step explanation:

We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.

We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.

We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.

Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.

Therefore, 4th lesson will end at 12:50 PM.

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3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

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3 years ago

Caroline’s two managers, Shawna and Morris, are having a meeting to discuss her performance. To prepare, Morris looks at Carolin

PSYCHO15rus [73]

I believe the answeris B

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3 years ago

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