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bulgar [2K]
3 years ago
5

-3 = x/4 + 5 using replacement set {-32, 8,32}

Mathematics
1 answer:
vichka [17]3 years ago
6 0

Answer:

-32

Step-by-step explanation:

-32/4=-8

-8+5=-3

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Which table shows data with variability?
masya89 [10]

Answer:

the table should show the data

3 0
3 years ago
Read 2 more answers
Solve this system of linear equations. -14x + 11y = 23 7x - 3y = 37 <br> x=? y=?
lesya692 [45]
<span> -14x + 11y = 23
+2(7x - 3y = 37)
----------------------
   0 + 5y = 97
y  = 97/5
y = 19.4

7x - 3(19.4) = 37
7x - 58.2 = 37
7x = 37 + 58.2
7x = 95.2
x = 95.2/7
x = 13.6

Check

-14(13.6) + 11(19.4) = 23
-190.4 + 213.4 = 23
</span>
3 0
3 years ago
The angle of depression from the top of a lighthouse to a boat is 27*. if the direct distance from the top of lighthouse to the
alisha [4.7K]

Answer:

Correct answer:  Db = 411 .18 ft

Step-by-step explanation:

Given:

α = 27°  angle of depression

Dt = 462 ft  distance from the top of lighthouse to the boat

Db = ?   distance from the base of the lighthouse to the boat

Here we have a right triangle with hypotenuse Dt and one leg Db.

By definition

cos α = Db / Dt  ⇒ Db = Dt · cos α

Db = 462 · cos 27° = 462 · 0.89 = 411 .18 ft

Db = 411 .18 ft

God is with you!!!

5 0
3 years ago
Smith's age is 8 and his mother is 42.in how many years will the mother be three times as his son​
frozen [14]
Let’s make an equation
Let’s say x = amount of years after
Smith = 8, mother = 42
3(8 + x) = 42 + x
24 + 3x = 42 + x
2x = 18, x = 9
Solution: after 9 years
3 0
3 years ago
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
3 years ago
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