All categories

3 years ago

Can you help with this? Thank you!

Mathematics

2 answers:

Gnom [1K]3 years ago

5 0

To solve for j, cross multiply:

4 x 45 = 18 x j

180 = 18j

Divide both sides by 18:

j = 10

ExtremeBDS [4]3 years ago

3 0

j=10

if you dont need an explanation dont read this:

firstly you reduce the 4/18 by 2 (<em>basically simplifying</em>) , which then becomes 2/9..

then you cross the 2 by 45 and 9 to j (<em>you multiply 2x45 and 9xj=9j</em>)

so it equals to 90=9j

then you divide both sides by 9

j=10

You might be interested in

Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i

aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

$P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175$

Positive when there is raritanium:

98% of 13%

$P(A) = 0.98*0.13 = 0.1274$

What is the probability the rock sample actually contains raritanium?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967$

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0

3 years ago

You have $60 and your sister has 120 you are saving $14 per week and your sister is saving $10 per week how long will it be befo

hodyreva [135]

Answer:

15 weeks and you both will have $270

Explanation:

60+14x=120+10x

4x=60

x=15 weeks

amount= 60+14*15= $270

5 0

3 years ago

Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c

slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 16.000

Sample mean, $\bar{x}$ = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338$

Thus, the value of test statistic is 1.338

4 0

4 years ago

What is the total area of the shape

fomenos

84cm^2. Hope this helps

4 0

3 years ago

Please any help with steps

Arada [10]

I think the answer is 1/2. C.

7 0

3 years ago

Read 2 more answers