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Dima020 [189]
3 years ago
12

Can you help with this? Thank you!

Mathematics
2 answers:
Gnom [1K]3 years ago
5 0

To solve for j, cross multiply:

4 x 45 = 18 x j

180 = 18j

Divide both sides by 18:

j = 10

ExtremeBDS [4]3 years ago
3 0

j=10

if you dont need an explanation dont read this:

firstly you reduce the 4/18 by 2 (<em>basically simplifying</em>) , which then becomes 2/9..

then you cross the 2 by 45 and 9 to j (<em>you multiply 2x45 and 9xj=9j</em>)

so it equals to 90=9j

then you divide both sides by 9

j=10

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ki77a [65]

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3 years ago
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mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Line a passes through (2, 10) and (4, 13).  So, slope of this line is

m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}

Line b passes through (4, 9) and (6, 12).  So, slope of this line is

m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}

Line c passes through (2, 10) and (4,9).  So, slope of this line is

m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}

Product of slopes of to perpendicular lines is -1.

m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1

m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

Therefore, any of these lines are not perpendicular to each other.

8 0
3 years ago
14. One angle of a triangle has measure 23° 40' and another
pishuonlain [190]

Hello!

 180 °- 23°40' - 41°19'

=> 180° - 64° 59'

 => 115° 1'

3 0
2 years ago
You want to test your newly created Web site, so you have 250 people access it from random locations at random times. Of the peo
Arte-miy333 [17]

Answer: 505

Step-by-step explanation:

The formula to find the sample size n , if the prior estimate of the population proportion (p) is known:

n= p(1-p)(\dfrac{z}{E})^2 , where E=  margin of error and z = Critical z-value.

Let p be the population proportion of crashes.

Prior sample size = 250

No. of people experience computer crashes = 75

Prior proportion  of crashes p=\dfrac{75}{250}=0.3

E= 0.04

From z-table , the z-value corresponding to 95% confidence interval = z=1.96

Required sample size will be :

n=0.3(1-0.3)(\dfrac{1.96}{0.04})^2 (Substitute all the values in the above formula)

n= (0.21)(49)^2= 0.21\times2401

n= 504.21\approx505   (Rounded to the next integer.)

∴ Required sample size = 505

6 0
3 years ago
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