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mixer [17]
3 years ago
11

if we ignore a resistance, a falling body will fall 16t^2 in T seconds what is the average velocity between T=6 and T=6.1? Round

your answer to two decimal places if necessary

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = 262.4 m/s

Step-by-step explanation:

The distance fallen s = 16t^2

The velocity v =  = 32t

If we substitute the values of t into the velocity v, we'll have

t = 8 s,     V1 = 32 x 8 = 256 m/s

 t = 8.4 s,  V2 = 32 x 8.4 = 268.8 m/s

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