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mixer [17]
3 years ago
11

if we ignore a resistance, a falling body will fall 16t^2 in T seconds what is the average velocity between T=6 and T=6.1? Round

your answer to two decimal places if necessary

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = 262.4 m/s

Step-by-step explanation:

The distance fallen s = 16t^2

The velocity v =  = 32t

If we substitute the values of t into the velocity v, we'll have

t = 8 s,     V1 = 32 x 8 = 256 m/s

 t = 8.4 s,  V2 = 32 x 8.4 = 268.8 m/s

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Answer:

The area of the shaded region is about 38.1 square centimeters.

Step-by-step explanation:

We want to find the area of the shaded region.

To do so, we can first find the area of the sector and then subtract the area of the triangle from the sector.

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\displaystyle A=\pi r^2\cdot \frac{\theta}{360^\circ}

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\displaystyle \begin{aligned}A&=\pi(6)^2\cdot \frac{150}{360}\\ &=36\pi\cdot \frac{5}{12}\\&=3\pi \cdot 5\\&=15\pi \text{ cm}^2\end{aligned}

Now, we can find the area of the triangle. We can use an alternative formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle between them.

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\displaystyle A=\frac{1}{2}(6)(6)\sin(150)=18\sin(150)

The area of the shaded region is equivalent to the sector minus the triangle:

A_{\text{shaded}}=A_{\text{sector}}-A_{\text{triangle}}

Therefore:

A_{\text{shaded}}=15\pi -18\sin(150)

Use a calculator:

A_{\text{shaded}}=38.1238...\approx 38.1\text{ cm}^2

The area of the shaded region is about 38.1 square centimeters.

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Step-by-step explanation:

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